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1 answer:
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Answer:
see explanation
Step-by-step explanation:
Given f(x) then the derivative f'(x) is
f'(x) = lim(h tends to 0 )
= lim ( h to 0 )
= lim ( h to 0 )
= lim( h to 0 )
= lim( h to 0 )
= lim ( h to 0 ) ← cancel h on numerator/ denominator
= lim ( h to 0 ) 4(2x + h) ← let h go to zero
f'(x) = 8x
Answer:
600 m³
Step-by-step explanation:
Given:
- length of swimming pool = 30 m
- width of swimming pool = 10 m
- depth at deep end = 3 m
- depth at shallow end = 1 m
To find the volume of the water in the pool, find the area of a cross section (see attached image) and multiply it by the width of the pool.
<u>Area of cross section</u>
= area of rectangle - area of triangle
= (3 × 30) - [1/2 × 30 × (3 - 1)]
= 90 - 30
= 60 m²
<u>Volume of pool</u>
= area of cross section × width
= 60 × 10
= 600 m³
