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krek1111 [17]
2 years ago
15

QUICK whoever gives correct answer will get brainliest thank you.​

Mathematics
1 answer:
kenny6666 [7]2 years ago
6 0

Answer: B

Step-by-step explanation:

For a relation to be a function, each input value can only have one corresponding output.

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I'm not really good at clearing fractions I need help with this problem please!
Sonja [21]
1/4x + 3 = 2x - 5/8

Find least common multiplier of 4x,8 is  8x

Multiply by LCM = 8x

1/4 x * 8 x + 3 * 8 x = 2 x * 8 x - 5/8 * 8 x

Refine:

2 + 24 = 16 x² - 5 x

Subtract 16 x² - 5 x from both sides:

2 + 24 x - ( 16 x² -5 x) = 16 x² - 5 x - (16 x²-5 x)

Refine: - 16 x² - 29 x + 2 = 0

Solving with the quadratic formula :

for a = - 16 , b = 29 and c = 2

x1 = - 29 √ 29² - 4(-16)*2
        -----------------------------
              2 (-16)

x1 = - √ 969  - 29
      ---------------------
                32


x2 = - 29 - √ 29² -4(-16)*2
        -----------------------------
               2(-16)

x2 = √ 969  + 29
      ---------------------
                32

The final solutions to the quadratic equation are:


x1 = - √ 969 - 29
      -------------------
              32

x2 = √ 969 + 29
      -------------------
             32


hope this helps!

3 0
3 years ago
Help with these
Vilka [71]

-7/10 divided by 2/5 is -35/20 or -7/4 in the simplest form

-1/4 times (-4/3) is 4/12 or 1/3 in the simplest form

-3 1/3 or -10/3 times by -2 7/10 or -27/10 is 270/30 or 9

-10 2/7 or -72/7 divided by -4 4/11 or -48/11 is 792/336 or 33/14 in the simplest from

5 0
3 years ago
Inverse function of exponential function
marta [7]

(( ln(3x) \div 2)  - 1) \div 4

3 0
3 years ago
Find an​ nth-degree polynomial function with real coefficients satisfying the given conditions.
lesya692 [45]

Answer:

\displaystyle f(x) = -2(x-2)(x^2+4)

Step-by-step explanation:

We want to find a third degree polynomial with zeros <em>x </em>= 2 and <em>x</em> = 2i and f(-1) = 30.

First, note that by the Complex Root Theorem, since <em>x</em> = 2i is a root, <em>x</em> = -2i must also be a root.

Hence, we will have the three factors:

\displaystyle f(x) = a(x-(2))(x-(2i))(x-(-2i))

Where <em>a</em> is the leading coefficient.

Expand and simplify the second and third factors:

\displaystyle \begin{aligned} (x-(2i))(x-(-2i)) &= (x-2i)(x+2i) \\ \\ &= x(x-2i)+2i(x-2i) \\ \\ &= (x^2 - 2ix) + (2ix - 4i^2) \\ \\ &=x^2 + 4\end{aligned}

Hence:

\displaystyle f(x) = a(x-2)(x^2+4)

Since f(-1) = 30:

\displaystyle \begin{aligned}  f(x) &= a(x-2)(x^2+4) \\ \\ (30) &= a((-1)-2)((-1)^2+4) \\ \\ 30 &= -15a \\ \\ a&= -2\end{aligned}

In conclusion, third degree polynomial function is:

\displaystyle f(x) = -2(x-2)(x^2+4)

5 0
3 years ago
Pleaseee answer correctly !!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!!!
viktelen [127]

Answer:

G and E

Step-by-step explanation:

6 0
3 years ago
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