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3 years ago

T-1 —— = 12. What is t 2 7+a -4= ——. What is a 5

Mathematics

1 answer:

Nana76 [90]3 years ago

5 0

For 3.) you would multiply both sides by 2

t-1=24

Then add

t=22

For 4.) multiply by 5

-20= 7+a

Then subtract

-27=a Hope this helps!

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a photograph is printed in the center of a piece of paper measuring 7 cm by (x + 8) cm. The photo measures 5 cm by (x +6) cm . T

Nadusha1986 [10]

The paper is 7 cm by (x + 8) cm.

A photo is 5 cm by (x + 6) cm, and is printed in the middle of the paper.

The area of the border/space around the photo is 50 cm².

To find the area of the border around the photo, you find the area of the paper and subtract it by the area of the photo.

The area of the paper:

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(7x + 56) - (5x + 30) = 50

Distribute/multiply the - to (5x + 30)

7x + 56 - 5x - 30 = 50

Combine like terms

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Subtract 26 on both sides

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b -10 X y = -10y
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d b X (-1) = -b
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i -7 X 8n = -56n
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3 Simplify by collecting like terms:
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b 11x-2y-5x+7y=(11-5)x+(-2+7)y=(6)x+(5)y=6x+5y
c 3m+2g-5g-4m=(3-4)m+(2-5)g=(-1)m+(-3)g=-m-3g
d 6a-7-9a+10=(6-9)a+(-7+10)=(-3)a+(3)=-3a+3
e 7p-2q-6p+3q=(7-6)p+(-2+3)q=(1)p+(1)q=p+q
f 3x+7-12-5x=(3-5)x+(7-12)=(-2)x+(-5)=-2x-5
g 2ab+3bc-5ab+bc=(2-5)ab+(3+1)bc=(-3)ab+(4)bc=-3ab+4bc
h 6t^2+3t-5t^2-8t=(6-5)t^2+(3-8)t=(1)t^2+(-5)t=t^2-5t
i 9y-6z-9y+5z=(9-9)y+(-6+5)z=(0)y+(-1)z=0-z=-z
j 2k-3k^2-4k+k^2=(2-4)k+(-3+1)k^2=(-2)k+(-2)k^2=-2k-2k^2
k 10t+5w+t-7w=(10+1)t+(5-7)w=(11)t+(-2)w=11t-2w
l 7a-3b-8a-5b=(7-8)a+(-3-5)b=(-1)a+(-8)b=-a-8b

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2 years ago