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marusya05 [52]
3 years ago
6

Describe what would be observed if a strip of magnesium ribbon was added to dilute hydrochloric acid.

Chemistry
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:

A solid (s) magnesium strip or ribbon is added to hydrochloric acid, an aqueous solution (aq) . The reaction produces aqueous magnesium chloride and gaseous (g) hydrogen gas, which as you can see bubbles out of solution.

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What is the concentration of an NaOH solution if 80.0 mL of 0.950M HCl acid is required to neutralize 50.0 mL of the base soluti
iogann1982 [59]

The question requires us to calculate the concentration of a NaOH solution, given the amount and concentration of HCl required to neutralize 50.0 mL of this base solution.

The following information was provided by the question:

<em>concentration of HCl solution = C(HCl) = 0.950 M = 0.950 mol/L</em>

<em>volume of HCl solution = V(HCl) = 80.0 mL</em>

<em>volume of NaOH solution = V(NaOH) = 50.0 mL</em>

To solve this problem, we need to understand what happens when NaOH and HCl react. A neutralization reaction occurs between a strong acid, such as HCl, and a strong base, such as NaOH, where the amount of H+ and OH- ions in solution are equal. We can write their reaction as:

<em>NaOH + HCl -> NaCl + H2O</em>

When the base is completely neutralized by the acid, it means that:

number of moles of NaOH = number of moles of HCl

The equality above is what we'll use to start our calculations.

Another important information to this question is that, by definition, the molar concentration is the number of moles of a compound divided by the volume of the solution:

\text{molarity = }\frac{number\text{ of moles (mol)}}{\text{volume (L)}}\to\text{ M=}\frac{n}{V}

Since we have the equality between the number of moles of acid and base, we can rewrite the equation above as:

n=M\times V

and use this to calculate the molar concentration (M) of NaOH.

Thus, so far we have that:

n_{NaOH}=n_{HCl}\to M_{NaOH}\times V_{NaOH}=M_{HCl}\times V_{HCl}

Since the volume of NaOH, molarity of HCl and volume of HCl were provided by the question, we can rearrange the equation above to calculate the molarity of NaOH:

M_{NaOH}=\frac{M_{HCl}\times V_{HCl}}{V_{NaOH}}

And, at last, we can apply the values provided by the problem (note that the volume here is being used in mL instead of L; this is fine as long as the volume of both solutions, acid and base, are used with the same unit):

M_{NaOH}=\frac{(0.950\text{ mol/L)}\times(80.0\text{ mL)}}{(50.0\text{ mL)}}=1.52\text{ mol/L}

Therefore, the molar concentration of the NaOH solution is equal to 1.52 mol/L (or 1.52 M).

7 0
1 year ago
What does this symbol, 1/0N, mean?
Firdavs [7]

An element can be represented symbolically in terms of its atomic number and mass number as:

_{Z}^{A}\textrm{X}

where X = symbol of the element

A = atomic mass

Z = atomic number

In this case we have the representation as:

_{0}^{1}\textrm{n}

where n = symbol for neutron

mass number of neutron = 1

charge/atomic number of neutron = 0

Ans: D) A neutron of zero charge and one unit mass



5 0
3 years ago
The two products of photosynthesis are _____.
REY [17]

the plant gets sunlight to make its food and grow. hope this helps a bit

3 0
4 years ago
Read 2 more answers
At what temperature are the liquid and the vapour of Bromine in equilibrium (e.g. boiling point)?
irina [24]

Explanation:

Boiling point is defined as the point at which liquid state and vapor state of a substance are existing in equilibrium.

Equilibrium is defined as the state in which rate of forward and rate of backward reaction are equal to each other.

For example, Br(l) \rightleftharpoons Br(g)

So, when we boil bromine which is present in liquid state then at the boiling point its vapors will exist in equilibrium. And unless all the liquid state of bromine will not convert into vapors its temperature will not change.

Therefore, we can conclude that at boiling point the liquid and the vapur of Bromine are in equilibrium.

7 0
3 years ago
Where do the light-independent reactions take place in c3 photosynthesis?
QveST [7]

Answer:

chloroplast, more precisely in the stroma of the chloroplast

Explanation:

Chloroplasts are a type of chromoplasts that are located in photosynthetic plant cells and green algae.

They can be moved by amoeboid and contractile movements, and placed in the part of the cell that receives the most light. Photosynthetic algae usually have a large chloroplast, but plant cells have a few tens.

The internal medium of the chloroplast is called stroma, and it is composed of a solution of carbohydrates, lipids, protids, nucleic acids, pigments, nucleotides, salts and elements.

Its main function is to capture the light energy and use it in the synthesis of organic matter.

3 0
3 years ago
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