Answer:
Explanation:
Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many grams of A would be needed to give the same number of particles: as 7.5 grams of B? 20 as 2.5 grams? 12.5 as 12.5 grams? 37.5 as 1 gram? 2 Count the number of molecules in the diagram of water formation given in the lesson to complete the following ...
Answer:
Ethanol (boiling point 78°C) and methanol (boiling point 65°C) are two miscible liquids. There is only a small difference in their boiling points. These two liquids are separated from their mixture by fractional ths distillation.
When vapours of the mixture pass through the fractionating column, repeated liquefaction and vapourisation take place. Subsequently, the vapours of low boiling methanol enter the condenser from the fractionating column, condense to liquid and get collected in the round bottomed flask first. Similarly, ethanol with higher boiling point can be collected later in another round bottomed flask.
Answer:
x=2 (
Explanation:
Mass of 
is the mass of remaining sample, because it is a product of loss of drying from initial sample. This means that the mass of water is the mass has been lost.
after fing the masses of and water you must to find the amount of moles in both cases.
Now you must to find the ratio between both molecules:
So the water is two times copper(II) chloride. (
