Answer: Mass of silver deposited at the cathode is 37.1g
Explanation: According to Faraday Law of Electrolysis, the mass of substance deposited at the electrode (cathode or anode) is directly proportional to quantity of electricity passed through the electrolyte
Faraday has found that to liberate one gm eq. of substance from an electrolyte, 96500C of electricity is required.
+e− ==> Ag(s)
Given that
Current (I) = 8.5A
Time (t) = 65 *60 = 3900s
Quantity of electricity passed = 8.5*3900 =33150C
Molar mass of Ag= 108g
96500C will liberate 108g
33150C will liberate Xg
Xg= (108*33150)/96500
=37.1g
Therefore the mass of Ag deposited at the cathode is 37.1g.
The number of moles contained in each of the question are a) 3.935 and b) 0.001165 mol.
<h3>What are moles?</h3>
Moles are a quantity or amount of a substance. Denoted by n.
To calculate moles, mass is divided by the molar mass
n = m/M
mass is divided by the molar mass
a) 230 grams of NaCl
n = m/M
molar mass of NaCl is 58.44 g/mol
n = 230 / 58.44 = 3.935 mol
b) 0.210 g of aspirin
n = m/M
molar mass of aspirin is 180.158 g/mol
n = 0.210 / 180.158 = 0.001165 mol
Thus, the moles are a) 3.935 and b) 0.001165 mol.
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I dont think with this much amount of information we can solve this...unless its an reversible reaction in that case free energy =0
Answer:
1.059 x 10^24 formula units
Explanation:
103/58.44 = 1.76 moles NaCl
1.76 x 6.022 x 10^23 = 1.059 x 10^24
Answer:
59.2 grams
Explanation:
We are given that 70.4% of the weight of the total 200 g of the concentration is made up of nitric acid, the remaining information is not required to solve the problem. Since water and nitric acid are the only components of the solution, the total weight of water is given by:

There are 59.2 grams of water in this solution.