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Crank
4 years ago
13

Which is an example of potential energy

Chemistry
1 answer:
den301095 [7]4 years ago
8 0

Answer:

A coiled spring.

Wheels on roller skates before someone skates.

An archer's bow with the string pulled back.

A raised weight.

Water that is behind a dam.

A snow pack (potential avalanche)

A quarterback's arm before throwing a pass.

A stretched rubber band

Explanation:

its prteey much energy that could potentialy happen

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Dilution of hcl because less no of mole of hcl would be reacting to form zncl2
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3 years ago
Read 2 more answers
This answer please :))
r-ruslan [8.4K]

Answer: ya this one

Explanation: this is the one

4 0
3 years ago
Which is a true statement about an exterior angle of a triangle?
wolverine [178]

The only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

<h3>What is a triangle?</h3>

A triangle can be defined as a one of the plane shapes which has three sides and three angles

So therefore, the only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

Learn more about triangles:

brainly.com/question/2217700

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7 0
2 years ago
10 To draw a perfect circle, you'll need: A A protractor B. A sextant С A compass D A spirograph 10 of 10​
mestny [16]

Answer:

B

Explanation:

Two quick google searches later I grace you with the google has bestowed upon me

7 0
3 years ago
A 27.3 g marble sliding to the right at 21.0 cm/s overtakes and collides with a 11.7 g marble moving in the same direction at 12
NISA [10]

Answer:

The answer to this is

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

Explanation:

To solve the question, let us list out the given variables and their values

Mass of first marble m1 = 27.3g

Velocity of the first marble v1 = 21.0 cm/s

Mass of second marble m2 = 11.7g

Velocity of the second marble v2 = 12.6 cm/s

After collision va1 = unknown and va2 = 23.7 cm/s

From Newton's second law of motion, force = rate of change of momentum produced

Hence m1v1 + m2v2 = m1va1 + m2va2 or

va1 = (m1v1 + m2v2 - m2va2)÷m2 or (720. 72-277.29)÷m1 → va1 = 16.24 cm/s

The velocity of the 27.3Kg marble after collision is = 16.24 cm/s

4 0
3 years ago
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