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ASHA 777 [7]
2 years ago
5

Which is a true statement about an exterior angle of a triangle?

Chemistry
1 answer:
wolverine [178]2 years ago
7 0

The only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

<h3>What is a triangle?</h3>

A triangle can be defined as a one of the plane shapes which has three sides and three angles

So therefore, the only true statement about an exterior angle of a triangle from the above is that it forms a linear pair with one of the interior angles of the triangle.

Learn more about triangles:

brainly.com/question/2217700

#SPJ1

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Rank the following substances in order from most soluble in water to least soluble in water: methane, CH4; 2-butanol, C4H9OH; po
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Answer:

Arranged in order of most soluble to least soluble in water:

KCl > CH_{4}  > C_{4} H_{9} OH > C_{3}H_{8}

Explanation:

Water is a polar solvent due to the electric charge it possesses. Hence it would only dissolve polar molecules.

Non-polar molecules would be dissolved by non-polar solvents.

Short chain alcohols are more soluble than butanol, but generally the polar -OH group is soluble in water.

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15. What are the outer electrons of an atom that have to ability to create<br> chemical bonds? *
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valence electron

Explanation:

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Which statement below correctly describes the relationship between Q and K for both reactions? Are these reactions spontaneous a
nikklg [1K]

Answer:

Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Explanation:

Hello,

In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:

A->B;\Delta _rG^o=-13 kJ/mol

C ->D ;\Delta _rG^o=3.5 kJ/mol

The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.

For each case, the reaction quotient is:

Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167

A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:

K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249

Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.

Best regards.

6 0
3 years ago
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