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3 years ago

I need help plz and show prove this is for 13 points

Mathematics

1 answer:

kiruha [24]3 years ago

8 0

Ok I hope this is what you needed!

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The figure shows two intersecting lines and the measures of the resulting angles. Write an equation to help you solve for x. The

Svetlanka [38]

Given:

The given figure shows the intersection of the two lines.

The angles formed by the intersection of the two lines are (3x - 8)° and (2x + 12)°

We need to determine the equation to solve for x and to find the value of x.

Equation to solve for x:

Since, the two angles (3x - 8)° and (2x + 12)° are vertically opposite angles and the vertical angles are always equal.

Hence, we have;

$3x-8=2x+12$

Thus, the equation to solve for x is $3x-8=2x+12$

Value of x:

The value of x can be determined by solving the equation $3x-8=2x+12$

Thus, we have;

$x-8=12$

$x=20$

Thus, the value of x is 20.

3 0

3 years ago

Write and solve the following expression: The sum of 7 and twice a number is 15

Nastasia [14]

Answer:

It would be 7 + 2x = 15

8 0

3 years ago

What is the solution to the problem 2y+3=4y+2

yulyashka [42]

Answer:

y = 1/2

Step-by-step explanation:

Step 1: Solve for y

2y + 3 = 4y + 2

2y + 3 - 2 - 2y = 4y + 2 - 2 - 2y

1 / 2 = 2y / 2

1/2 = y

Answer: y = 1/2

8 0

3 years ago

Read 2 more answers

Find the greatest number that will divide 63, 45 and 69 so as to leave the same remainder.

jeka57 [31]

Answer:

Step-by-step explanation:

Let n be unknown divisor and a be the same remainder, then

$63=q_1\cdot n+a\\ \\45=q_2\cdot n+a\\ \\69=q_3\cdot n+a$

Subtract a from all equalities:

$63-a=q_1\cdot n\\ \\45-a=q_2\cdot n\\ \\69-a=q_3\cdot n$

Subtract them:

$63-45=(q_1-q_2)n\Rightarrow 18=(q_1-q_2)n\\ \\69-63=(q_3-q_1)n\Rightarrow 6=(q_3-q_1)n\\ \\69-45=(q_3-q_2)n\Rightarrow 24=(q_3-q_2)n$

The greatest number is 6. When you divide numbers 63, 45, 69 by 6, you'll get remainders 3, 3, 3, respectively.

7 0

3 years ago

What fraction would you add to 29/6 to make 4

Zigmanuir [339]

Keeping in mind that 29/6 is greater than 4, is actually 4 and 5/6, so the amount we'll "add" will be a negative one.

$\bf \cfrac{29}{6}+x=4\implies x=4-\cfrac{29}{6}\implies x=\cfrac{4}{1}-\cfrac{29}{6}\implies x=\cfrac{(6)4-(1)29}{6}
\\\\\\
x=\cfrac{24-29}{6}\implies x=\cfrac{-5}{6}\\\\
-------------------------------\\\\
\cfrac{29}{6}+\left( -\cfrac{5}{6} \right)=4$

8 0

3 years ago