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Andru [333]
3 years ago
9

I need help plz and show prove this is for 13 points

Mathematics
1 answer:
kiruha [24]3 years ago
8 0
Ok I hope this is what you needed!

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The figure shows two intersecting lines and the measures of the resulting angles. Write an equation to help you solve for x. The
Svetlanka [38]

<u>Given</u>:

The given figure shows the intersection of the two lines.

The angles formed by the intersection of the two lines are (3x - 8)° and (2x + 12)°

We need to determine the equation to solve for x and to find the value of x.

<u>Equation to solve for x:</u>

Since, the two angles (3x - 8)° and (2x + 12)° are vertically opposite angles and the vertical angles are always equal.

Hence, we have;

3x-8=2x+12

Thus, the equation to solve for x is 3x-8=2x+12

<u>Value of x:</u>

The value of x can be determined by solving the equation 3x-8=2x+12

Thus, we have;

x-8=12

     x=20

Thus, the value of x is 20.

3 0
3 years ago
Write and solve the following expression:<br><br>The sum of 7 and twice a number is 15
Nastasia [14]

Answer:

It would be 7 + 2x = 15

8 0
3 years ago
What is the solution to the problem 2y+3=4y+2
yulyashka [42]

Answer:

y = 1/2

Step-by-step explanation:

<u>Step 1:  Solve for y</u>

2y + 3 = 4y + 2

2y + 3 - 2 - 2y = 4y + 2 - 2 - 2y

1 / 2 = 2y / 2

1/2 = y

Answer:  y = 1/2

8 0
3 years ago
Read 2 more answers
Find the greatest number that will divide 63, 45 and 69 so as to leave the same remainder.
jeka57 [31]

Answer:

6

Step-by-step explanation:

Let n be unknown divisor and a be the same remainder, then

63=q_1\cdot n+a\\ \\45=q_2\cdot n+a\\ \\69=q_3\cdot n+a

Subtract a from all equalities:

63-a=q_1\cdot n\\ \\45-a=q_2\cdot n\\ \\69-a=q_3\cdot n

Subtract them:

63-45=(q_1-q_2)n\Rightarrow 18=(q_1-q_2)n\\ \\69-63=(q_3-q_1)n\Rightarrow 6=(q_3-q_1)n\\ \\69-45=(q_3-q_2)n\Rightarrow 24=(q_3-q_2)n

The greatest number is 6. When you divide numbers 63, 45, 69 by 6, you'll get remainders 3, 3, 3, respectively.

7 0
3 years ago
What fraction would you add to 29/6 to make 4
Zigmanuir [339]
Keeping in mind that 29/6 is greater than 4, is actually 4 and 5/6, so the amount we'll "add" will be a negative one.

\bf \cfrac{29}{6}+x=4\implies x=4-\cfrac{29}{6}\implies x=\cfrac{4}{1}-\cfrac{29}{6}\implies x=\cfrac{(6)4-(1)29}{6}&#10;\\\\\\&#10;x=\cfrac{24-29}{6}\implies x=\cfrac{-5}{6}\\\\&#10;-------------------------------\\\\&#10;\cfrac{29}{6}+\left( -\cfrac{5}{6} \right)=4
8 0
3 years ago
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