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Kisachek [45]
2 years ago
5

How do I find the variable?

Mathematics
1 answer:
velikii [3]2 years ago
7 0

Answer:

x = 8

Step-by-step explanation:

Step 1:

9x = 72        Def. of an isosceles triangle

Step 2:

x = 72 ÷ 9        Divide

Answer:

x = 8

Hope This Helps :)

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Write the equation of a line, in Point slope form that passes through (5,6) and has a slope of -3​
Mademuasel [1]

Answer:

y = -3x + 21

Step-by-step explanation:

(5,6)

y = mx + b

6 = -3 × 5 + b

solving for b

b = 6 - (-3)(5)

b = 21

Therefore,

y = -3x + 21

7 0
2 years ago
$1800 at 6.5% for 30 months
nasty-shy [4]
1800×6.5%×30=b
b-1800=a

a) $1,710

b) $3,510
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3 years ago
in a class, 3/4 of the class like to go to the movies, 2/3 like action movies... how many like action movies in the class
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8 0
3 years ago
et f(x) = x + |2x − 3|. Find all solutions to the equation f(x) = 12. (Enter your answers as a comma-separated list. If an answe
Alinara [238K]

Answer:

1. {5,-9}

2.{4}

3.{9/2}

Step-by-step explanation:

The equation f(x)=x+\lvert 2x-3 \rvert=12 can be solved as follows:

x+\lvert 2x-3 \rvert =12\,\,\,\text{(given equation)}

\lvert 2x-3 \rvert =12-x

2x-3=12-x\,\,\text{or}\,\,2x-3=-(12-x)

3x=15\,\,\text{or}\,\,\x=-9

Then, the solutions of the equation are x=5, x=-9.

Now, if g(x)=5x-3+\lvert x+4\rvert, we can solve the equation g(a)=4a+9 as follows:

5a-3+\lvert a+4 \rvert =4a+9

\lvert a+4\rvert =4a+9-5a+3

a+4 =-a+12\,\,\text{or}\,\,a+4=-(-a+12)

2a=8\,\,\text{or}\,\,4=12

So, the unique solution of this last equation is a=4

The last equation is h(x-1)=x-3, where h(x)=\lvert x \rvert -2x+5.. To solve this equation we can proceed as follows:

h(x-1)=x-3

\lvert x-1\rvert -2(x-1)+5=x-3

\lvert x-1 \rvert -2x+2+5=x-3

\lvert x-1\rvert =3x-10

x-1=3x-10\,\,\text{or}\,\,x-1=-(3x-10)

-2x=-9\,\,\text{or}\,\,4x=11

x=9/2\,\,\text{or}\,\,x=11/4

But, x=11/4 is not a solution of this equation. So the unique solution is x=9/2.

8 0
2 years ago
What's the answer ?​
Leviafan [203]

Answer:

yes

Step-by-step explanation:

8 0
3 years ago
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