A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
R=10
because 10 divided by ten =1 +4 =5
<span>Binomial Problem with n = 50 and P(op) = 0.0.7
P(31<=50) = 1 - P(0<=x<=30) = 1 - binomcdf(50,0.7,30) = 1-0.0848 = 0.9152
</span>
Answer:
less than, this is scaling dude
Step-by-step explanation:
Answer:
The 4th one: 3^2 + 13^2 = x^2
Step-by-step explanation:
The <u>pythagorean theorem</u> is a^2 + b^2 = c^2. In this case 3 is a, 13 is b, and x is c.
happy to help
