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KiRa [710]
3 years ago
15

2. What is the difference between electric potential energy and gravitational potential energy? Name one

Physics
1 answer:
KiRa [710]3 years ago
8 0
Potential energy is the energy which is stored in a body when a certain force is applied on a body or work done on it.

Stretching a rubber band or spring, punching a non elastic ball, binding a cracker with string. In this the energy is stored in the objects after applying force on them and when released it is converted to other forms of energy like kinatic energy, chemical energy or sound

Gravitational potential energy is the energy stored in the object when work is done or applied in opposition with the gravitational force acting on it. e. g. water stored in dam, ball thrown in air or an elevator going up.

Obviously gravitational potential energy is the subset of all potential energies stored in the body..
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a 5kg block on a rough horizontal surface is attached to a light spring (force constant=1.6kN/m). the block passes through its e
natima [27]

Answer:

2.12 J

Explanation:

Initial kinetic energy = final elastic energy + work by friction

KE = EE + W

KE = ½ kx² + W

5 J = ½ (1600 N/m) (0.06 m)² + W

W = 2.12 J

5 0
3 years ago
Question:- A planet X moves in an elliptical path as shown below. At which point does the planet moves faster. Assume, Ethiopian
babymother [125]

We can get water from the sweat and exhaled breath of the people present in the space station.

<h3>How would you get water?​</h3>

We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through  condensation on the Space Station's walls.

So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.

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6 0
2 years ago
The graph shows a heating curve for water. Between which points on the graph would condensation occur?
Effectus [21]

Answer:

Between R and S

Explanation:

4 0
3 years ago
If the electric intensity between two parallel plates, placed 1cm apart is 104 NC-1and the direction of the field of this intens
ankoles [38]

The force of a charge in an electric field is:

\vec{F}_e=q\vec{E}

In this case we know the electric field is:

\vec{E}=104\hat{j}

and that the charge is that of the electron, then we have:

\begin{gathered} \vec{F}_e=-1.6\times10^{-19}(104\hat{j}) \\ \vec{F}_e=-1.664\times10^{-17}\text{ N} \end{gathered}

Therefore, the magnitude of the force is

1.664\times10^{-17}\text{ N}

and in points down.

The weight of the electron is:

\begin{gathered} W=1.67\times10^{-27}(9.98) \\ W=1.6366\times10^{-26} \end{gathered}

Making the quotient between the force we have:

\frac{1.664\times10^{-17}}{1.6366\times10^{-26}}=1.02\times10^9

Therefore, the electric force is approximately 1e9 times the weight.

3 0
2 years ago
An electron enters a region of space containing a uniform 2.71 × 10 − 5 2.71×10−5 T magnetic field. Its speed is 197 197 m/s and
Andrews [41]

Answer:

r = 0.0414mm

F = 757,692.3Hertz

Explanation:

If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as

F = qvBsintheta... 1

Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as

Fc = mv²/r... 2

Equating both forces

F = Fc

qvBsin theta = mv²/r

Since the body enters perpendicular to the field, theta = 90°

The equality becomes;

qvB sin90° = mv²/r

qvB = mv²/r

qB = mv/r

r = mv/qB

Given mass of the electron m = 9.11×10^-31kg

Velocity of the object v = 197m/s

Charge on the electron q = 1.6×10^-19C

Magnetic field B = 2.71×10^-5T

Substituting this value into the equation to get the radius r we have;

r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5

r = 1794.67×19^-31/4.336×10^-24

r = 413.89×10^-7

r = 0.0000414m

r = 0.0414mm

b) Frequency of the motion F = w/2π where w is the angular velocity

Since w = v/r

F = (v/r)/2π

F = v/2πr

F = 197/2π(0.0000414)

F = 757,692.3Hertz

6 0
4 years ago
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