Answer:
2.12 J
Explanation:
Initial kinetic energy = final elastic energy + work by friction
KE = EE + W
KE = ½ kx² + W
5 J = ½ (1600 N/m) (0.06 m)² + W
W = 2.12 J
We can get water from the sweat and exhaled breath of the people present in the space station.
<h3>How would you get water?</h3>
We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through condensation on the Space Station's walls.
So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.
Learn more about water here: brainly.com/question/1313076
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The force of a charge in an electric field is:

In this case we know the electric field is:

and that the charge is that of the electron, then we have:

Therefore, the magnitude of the force is

and in points down.
The weight of the electron is:

Making the quotient between the force we have:

Therefore, the electric force is approximately 1e9 times the weight.
Answer:
r = 0.0414mm
F = 757,692.3Hertz
Explanation:
If the body enters space with uniform magnetic field B, the force experienced by the object is expressed as
F = qvBsintheta... 1
Also, if the body undergoes a circular motion, the force experienced by the body in a circular path is given as
Fc = mv²/r... 2
Equating both forces
F = Fc
qvBsin theta = mv²/r
Since the body enters perpendicular to the field, theta = 90°
The equality becomes;
qvB sin90° = mv²/r
qvB = mv²/r
qB = mv/r
r = mv/qB
Given mass of the electron m = 9.11×10^-31kg
Velocity of the object v = 197m/s
Charge on the electron q = 1.6×10^-19C
Magnetic field B = 2.71×10^-5T
Substituting this value into the equation to get the radius r we have;
r = 9.11×10^-31 × 197/1.6×10^-19 × 2.71×10^-5
r = 1794.67×19^-31/4.336×10^-24
r = 413.89×10^-7
r = 0.0000414m
r = 0.0414mm
b) Frequency of the motion F = w/2π where w is the angular velocity
Since w = v/r
F = (v/r)/2π
F = v/2πr
F = 197/2π(0.0000414)
F = 757,692.3Hertz