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11111nata11111 [884]
3 years ago
11

If the current through a resistor is 12 A and the voltage drop is 12 V, what is the power absorbed by the resistor? Answer to th

e nearest 1 W. Assume the power equation is positive.
Physics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

144 W

Explanation:

The power absorbed by a resistor is the product of the current passing through it and the voltage drop across it. Hence

P=IV

P=12\text{ A}\times12\text{ V}=144 \text{ W}

Other variations of this formula are derived using Ohm's law, V=IR

P=I^2R=\dfrac{V^2}{R}

R is the resistance of the resistor. It is what causes the voltage drop.

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A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an obser
Ede4ka [16]

Answer:

0.384c

Explanation:

To find the speed of the pursuit ship relative to the cruiser you use the following relativistic equation:

u'=\frac{u-v}{1-\frac{uv}{c^2}}

u': relative speed

u: speed of the pursuit ship = 0.8c

v: speed of the cruiser = 0.6c

c: speed of light

You replace the values of the parameters to obtain u':

u'=\frac{0.8c-0.6c}{1-\frac{(0.6c)(0.8c)}{c^2}}=0.384c

Hence, the relative speed is 0.384c

4 0
3 years ago
What tension would you need to make a middle c (261.6 hz) fundamental mode on a 1 m string (for example, on a harp)? the linear
Allisa [31]
The frequency of middle C on a string is
f = 261.6 Hz.

The given linear density is
ρ = 0.02 g/cm = (0.02 x 10⁻³ kg)/(10⁻² m)
   = 0.002 kg/m

The length of the string is L = 1 m.

Let T =  the tension in the string (N).
The velocity of the standing wave is
v= \sqrt{ \frac{T}{\rho} }

In the fundamental mode, the wavelength, λ, is equal to the length, L.
That is
Because v = fλ, therefore
\sqrt{ \frac{T}{\rho} } =f \lambda = fL \\\\ \frac{T}{\rho} = (fL)^{2} \\\\ T = \rho (fL)^{2}

From given information, obtain
T = (0.002 kg/m)*(261.6 1/s)²*(1 m)²
   = 136.87 N

Answer: 136.9 N (nearest tenth)

4 0
3 years ago
If a single circular loop of wire carries a current of 62 A and produces a magnetic field at its center with a magnitude of 1.20
s2008m [1.1K]

Given Information:  

Current in loop = I = 62 A

Magnitude of magnetic field = B = 1.20x10⁻⁴ T

Required Information:  

Radius of the circular loop = r = ?  

Answer:  

Radius of the circular loop = 0.324 m

Explanation:  

In a circular loop of wire with radius r and carrying a current I  induces a magnetic field B which is given by

B = μ₀I/2r

Please note that for an infinitely straight long wire we use 2πr whereas for circular loop we use 2r

Where μ₀= 4πx10⁻⁷ is the permeability of free space

Re-arranging the equation yields

r = μ₀I/2B

r = 4πx10⁻⁷*62/2*1.20x10⁻⁴

r = 0.324 m

Therefore, the radius of this circular loop is 0.324 m

3 0
3 years ago
a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced
Alina [70]

Answer:

\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

\boxed{ \bold{ \sf H = I^2Rt}}

Substituting values of I, R & t in the equation:

\sf \implies H =  {5}^{2}  \times 100 \times 2 \\  \\ \sf \implies H = 25 \times 100 \times 2 \\  \\  \sf \implies H = 5000  \\  \\ \sf \implies H = 5 \: kWh

\therefore

Heat developed (H) in the electric iron = 15 kWh

3 0
3 years ago
HELP PLEASE HERE IS THE IMAGE
kari74 [83]

Answer:

I am pretty sure it's E because it splits through every layer

3 0
3 years ago
Read 2 more answers
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