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11111nata11111 [884]

3 years ago

11

If the current through a resistor is 12 A and the voltage drop is 12 V, what is the power absorbed by the resistor? Answer to th

e nearest 1 W. Assume the power equation is positive.

1 answer:

klasskru [66]3 years ago

7 0

Answer:

144 W

Explanation:

The power absorbed by a resistor is the product of the current passing through it and the voltage drop across it. Hence

$P=IV$

$P=12\text{ A}\times12\text{ V}=144 \text{ W}$

Other variations of this formula are derived using Ohm's law, $V=IR$

$P=I^2R=\dfrac{V^2}{R}$

$R$ is the resistance of the resistor. It is what causes the voltage drop.

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olga55 [171]

Answer:

9.22 s

Explanation:

One-quarter of a turn away is 1/4 of 2π, or π/2 which is approximately 1.57 rad

Let t (seconds) be the time it takes for the child to catch up with the horse. We would have the following equation of motion for the child and the horse:

For the child: $s_c = \omega_ct = 0.233t$

For the horse: $s_h = s_0 + a_ht^2/2 = 1.57 + 0.0136t^2/2 = 1.57 + 0.0068t^2$

For the child to catch up with the horse, they must cover the same angular distance within the same time t:

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$0.0068t^2 - 0.233t + 1.57 = 0$

$t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

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3 years ago

Which describes why people on earth can see light from the stars in the sky that are so far away?

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At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coeffi

Flura [38]

The given data is incomplete. The complete question is as follows.

At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36. Use these data to determine the speed of the car when the driver slammed on (and locked) the brakes. (why does the car's mass not matter?)

Explanation:

Let us assume that v is the final velocity and u is the initial velocity of the car. Let s be the skid marks and $\mu$ be the friction coefficient and m be the mass of car.

Hence, the given data is as follows.

v = 0, s = 84 m, $\mu$ = 0.36

According to Newton's law of second motion the expression for acceleration is as follows.

F = ma

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Thus, we can conclude that the speed of the car when the driver slammed on (and locked) the brakes is 24.36 m/s.

4 0

2 years ago