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Roman55 [17]
3 years ago
8

What is the greatest common factor of 12хуб + 60xy? — 24x°у? ?

Mathematics
1 answer:
Liula [17]3 years ago
3 0

The greatest common factor is 12xy

Explanation:

The given expression is 12xy^6+60xy

We need to determine the greatest common factor of the given expression.

The greatest common factor of two numbers is the largest number of the two numbers that divides them both.

Hence, from the given expression, let us common out the highest factor that divides the two numbers.

Thus, we have,

12xy^6+60xy=12xy(y^5+5y)

Thus, the largest number that divides both the terms is 12xy

Hence, the greatest common factor of the given expression is 12xy

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the atlanta braves are offering bobblehead to every 10th person who enters your fundraiser. the nashville predators are offering
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In this situation, attendee number thirty will be the first one o receive both the bobblehead and the ticket.

<h3>Which attendees will receive the bobblehead and the ticket?</h3>

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Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation
Leto [7]

Answer:

There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, so \mu = 47.88, \sigma = 3.09

What is the probability that the weight of a bag will be greater than the maximum allowable weight of 50 pounds?

That is P(X > 50)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{50 - 47.88}{3.09}

Z = 0.69

Z = 0.69 has a pvalue of 0.7549.

This means that P(X \leq 50) = 0.7549.

We also have that

P(X \leq 50) + P(X > 50) = 1

P(X > 50) = 1 - 0.7549 = 0.2451

There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.

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3 years ago
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