Answer:
Use a graphing calc or desmos to help guide you.
Step-by-step explanation:
In this situation, attendee number thirty will be the first one o receive both the bobblehead and the ticket.
<h3>Which attendees will receive the bobblehead and the ticket?</h3>
Bobblehead:
- Attendee number 10
- Attendee number 20
- Attendee number 30
Ticket:
- Attendee number 15
- Attendee number 30
<h3>What can be concluded?</h3>
It can be concluded the attendee number 30 will be the first one to receive both the ticket and the bobblehead.
Learn more about ticket in: brainly.com/question/14001767
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Answer:
45
Step-by-step explanation:
Answer:
C. 141.3
Step-by-step explanation:
Answer:
There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.
In this problem
Suppose that the weights of airline passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, so 
What is the probability that the weight of a bag will be greater than the maximum allowable weight of 50 pounds?
That is 
So



has a pvalue of 0.7549.
This means that
.
We also have that


There is a 24.51% probability that he weight of a bag will be greater than the maximum allowable weight of 50 pounds.