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pashok25 [27]
2 years ago
13

If high temperatures are most effective at killing microbes, what statement correctly explains why some food products are treate

d with temperatures below the boiling point of water?
Extremely high temperatures can destroy the food's desirable characteristics.

Extremely high temperatures would significantly lower the food's shelf life.

Extremely high temperatures promote the growth of some microbes.

Extremely high temperatures would destroy the food's nutritional value.
Chemistry
1 answer:
ZanzabumX [31]2 years ago
6 0

Answer: A

Explanation:

Good day mate :)

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3 years ago
Classify the following reactions: HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l) 2Cu(s)+O2(g)→2CuO(s) NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s) 2
Licemer1 [7]

Answer:

- HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l): neutralization.

- 2Cu(s)+O2(g)→2CuO(s): redox.

- NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s): precipitation.

- 2LiOH(aq)+H2SO4(aq)→Li2SO4(aq)+2H2O(l): neutralization.

- CaCl2(aq)+K2CO3(aq)→2KCl(aq)+CaCO3(s): precipitation.

Explanation:

Hello,

Based on the given reaction and their classification as redox, neutralization or precipitation, one obtains:

- HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l): neutralization as ammonia which is a base, is reacting with nitric acid which is an acid to yield ammonium nitrate which is a base.

- 2Cu(s)+O2(g)→2CuO(s): redox as both copper's and oxygen's oxydation states change by increasing by 2 and reducing by 2 respectively.

- NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s): precipitation as the inital reactants are soluble but the yielded silver chloride is not.

- 2LiOH(aq)+H2SO4(aq)→Li2SO4(aq)+2H2O(l): neutralization as lithium hydroxide which is a base reacts with sulfuric acid which is an acid to yield lithium sulfate which is a salt.

- CaCl2(aq)+K2CO3(aq)→2KCl(aq)+CaCO3(s): precipitation since both calcium chloride and potassium carbonate are soluble whereas calcium carbonate is not.

Best regards.

3 0
3 years ago
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