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3 years ago

Calculate the heat released when 25.0 grams of water freezes at 0 degree Celsius.

Chemistry

1 answer:

mafiozo [28]3 years ago

5 0

Answer:

= 8350 joules

Solution and explanation:

The heat of fusion refers to the quantity of heat released when a given amount of water freezes.

For example, 1 g of water releases 334 J when it freezes at 0°C.

Therefore; For 25.0 g of water.

Heat released = Mass of water × heat of fusion

= 25 g × 334 J/g

= 8350 Joules

Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.

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