Calculate the heat released when 25.0 grams of water freezes at 0 degree Celsius.
1 answer:
Answer:
= 8350 joules
Solution and explanation:
- The heat of fusion refers to the quantity of heat released when a given amount of water freezes.
- For example, 1 g of water releases 334 J when it freezes at 0°C.
Therefore; For 25.0 g of water.
Heat released = Mass of water × heat of fusion
= 25 g × 334 J/g
= 8350 Joules
Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.
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