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den301095 [7]
3 years ago
9

Calculate the heat released when 25.0 grams of water freezes at 0 degree Celsius.

Chemistry
1 answer:
mafiozo [28]3 years ago
5 0

Answer:

= 8350 joules

Solution and explanation:

  • The heat of fusion refers to the quantity of heat released when a given amount of water freezes.
  • For example, 1 g of water releases 334 J when it freezes at 0°C.

Therefore; For 25.0 g of water.

Heat released = Mass of water × heat of fusion

                        = 25 g × 334 J/g

                        = 8350 Joules

Hence, the amount of heat released when 25.0 g of water freezes at 0°C is 8350 J.

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A gas expands and does P-V work on the surroundings equal to 275 J. At the same time, it absorbs 216 J of heat from the surround
mafiozo [28]

Answer:

answer

Explanation:

sorry I do not know the answer, have a great day

7 0
3 years ago
Water (with density of 1000 kg/m3) with the mass flowrate of 10 kg/sec is flowing into an empty tank. The outlet volumetric flow
Montano1993 [528]

Explanation:

Apply the mass of balance as follows.

   Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank

         \frac{d}{dt}(\rho V) = 10 - \rho \times (0.01 h)

      \rho A_{c} \frac{dh}{dt} = 10 - (0.01) \rho h

   \frac{dh}{dt} + \frac{0.01 \rho h}{\rho A_{c}} = \frac{10}{\rho A_{c}}

          [/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] = \frac{10}{\rho A_{c}}

                       A_{c} = 0.01 m^{2}

              \frac{dh}{dt} + h = 1

                  \frac{dh}{dt} = 1 - h

               \frac{dh}{1 - h} = dt  

                \frac{ln(1 - h)}{-1} = t + C      

Given at t = 0 and V = 0  

                         A \times h = 0  

 or,                     h = 0

                 -ln(1 - h) = t + C

Initial condition is -ln(1) = 0 + C

                                C = 0  

                So,   -ln(1 - h) = t

or,                      t = ln (\frac{1}{1 - h})  ........... (1)

(a)    Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.

                    t = ln (\frac{1}{1 - h})  

                     t = ln (\frac{1}{1 - 0.6})  

                        = ln (\frac{1}{0.4})

                        = 0.916 seconds

(b)   As maximum height of water level in the tank is achieved at steady state that is, t = \infty.  

                    1 - h = exp (-t)

                    1 - h = 0  

                         h = 1

Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.

                 

8 0
3 years ago
How many atoms are there in 5.00 mol of sulphur (S)?
Mumz [18]

Answer:

3.01 × 10²⁴ atoms S

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

5.00 mol S

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />5.00 \ mol \ S(\frac{6.022 \cdot 10^{23} \ atoms \ S}{1 \ mol \ S} ) = 3.011 × 10²⁴ atoms S

<u />

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.011 × 10²⁴ atoms S ≈ 3.01 × 10²⁴ atoms S

6 0
3 years ago
Classify each of the following as a physical or a chemical change. Give
hjlf

Answer:

a is a physical changes

b is physical changes

c is a Chemical change

d is a physical changes

5 0
3 years ago
Today is a nonsense question day
Talja [164]

Answer:

We actually output other gases like methane lol

Explanation:

Well since most of the air we breathe is made up of nitrogen we also breathe out nitrogen

Source: da brain

Hope this helps you! :)

Please mark brainiest

It would help me a lot!

Thank you!

8 0
2 years ago
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