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Arada [10]
3 years ago
15

41.0 ml of barium hydroxide solution of molarity 3.41

Chemistry
1 answer:
Rzqust [24]3 years ago
6 0
Molarity = number of moles/volume (in L)

3.41 M = number of moles/0.041L

3.41 M x 0.041 L = ? number of moles
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For each of the following questions give the name of an element from period 2 lithium to neon which matches the description elem
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I need help identifying the type of reactions. Can anyone help?
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Answer:

Reaction 5: Decomposition reaction.

Reaction 6: Single replacement reaction

Reaction 7: Combination reaction.

Reaction 8: Combustion reaction.

Explanation:

<u><em>Reaction 5:</em></u>    2KClO₃ → 2KCl + 3O₂.

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  • In this reaction: potassium chlorate decomposes into two single components (potassium chloride and oxygen).
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<u><em>Reaction 6:</em></u> Zn + 2HCl → H₂ + ZnCl₂.

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  • A single-replacement reaction, a single-displacement reaction, is a reaction by which one (or more) element(s) replaces an/other element(s) in a compound.
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<u><em>Reaction 7:</em></u> N₂O₅ + H₂O → 2HNO₃.

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  • It is a combustion reaction.
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What is the difference between a substance at low temperature and one at high temperature
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Explained below.

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A substance at low temperature simply means that the average energy of molecular motion in that substance is low while at higher temperature, the average energy of molecular ml tip in that substance is high.

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A chemist prepares a solution of potassium dichromate by measuring out of potassium dichromate into a volumetric flask and filli
riadik2000 [5.3K]

Answer:

0.297 mol/L

Explanation:

<em>A chemist prepares a solution of potassium dichromate by measuring out 13.1 g of potassium dichromate into a 150 mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's potassium dichromate solution. Be sure your answer has the correct number of significant digits.</em>

<em />

Step 1: Calculate the moles corresponding to 13.1 g of potassium dichromate

The molar mass of potassium dichromate is 294.19 g/mol.

13.1 g × (1 mol/294.19 g) = 0.0445 mol

Step 2: Convert the volume of solution to L

We will use the relationship 1 L = 1000 mL.

150 mL × (1 L/1000 mL) = 0.150 L

Step 3: Calculate the concentration of the solution in mol/L

C = 0.0445 mol/0.150 L = 0.297 mol/L

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