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marin [14]
2 years ago
8

a retail owner can but a certain clock at an average price of $53 per clock and sell them for an average price of $84 per clock.

his fixed costs are $8000 per month and his variable cost is $5 per clock. (A) how many clocks must he sell each month to break even? (B) how many clocks must he sell to have a profit of $3000?
Mathematics
2 answers:
Wittaler [7]2 years ago
6 0

Answer:

  (A) 308 clocks

  (B) 423 clocks

Step-by-step explanation:

The contribution margin is the amount by which the selling price of the clock exceeds the cost of the clock. The contribution margin is used to figure the break-even point, and the amount of profit from sales.

  contribution margin = selling price - variable cost - purchase price

  contribution margin = $84 -5 -53 = $26

__

<h3>(A)</h3>

To break even, the contribution margin from 'b' clocks must equal or exceed the owner's fixed cost:

  26b ≥ 8000

  b ≥ 8000/26

  b ≥ 307.7

The owner must sell 308 clocks each month to break even.

__

<h3>(B)</h3>

To make a profit of $3000, the owner must sell enough clocks to cover the $8000 fixed cost and contribute an additional $3000. That is, the total contribution margin from selling p clocks must be about $3000+8000 = $11000.

  26p ≈ 11000

  p ≈ 11000/26 ≈ 423.08

The owner must sell about 423 clocks each month to earn a profit of about $3000.

__

<em>Additional comment</em>

Selling 423 clocks will yield a profit of $2998.

Butoxors [25]2 years ago
4 0

Answer:

the answer is this

Step-by-step explanation:

To calculate the break-even point in units use the formula: Break-Even point (units) = Fixed Costs ÷ (Sales price per unit – Variable costs per unit) or in sales dollars using the formula: Break-Even point (sales dollars) = Fixed Costs ÷ Contribution Margin

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Dahasolnce [82]

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<u>Solution:</u>

Given:- For a certain prospectus Callie can prepare it two hours faster than Terry can

Let the time taken by Terry be "a" hours

So, the time taken by Callie will be (a-2) hours

Hence, the efficiency of Callie and Terry per hour is \frac{1}{a-2} \text { and } \frac{1}{a} \text { respectively }

If they work together they can do the entire prospectus in five hours

\text {So, } \frac{1}{a-2}+\frac{1}{a}=\frac{1}{5}

On cross-multiplication we get,

\frac{a+(a-2)}{(a-2) \times a}=\frac{1}{5}

\frac{2 a-2}{(a-2) \times a}=\frac{1}{5}

On cross multiplication ,we get

\begin{array}{l}{5 \times(2 a-2)=a \times(a-2)} \\\\ {10 a-10=a^{2}-2 a} \\\\ {a^{2}-2 a-10 a+10=0} \\\\ {a^{2}-12 a+10=0}\end{array}

<em><u>using quadratic formula:-</u></em>

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

x=\frac{12 \pm \sqrt{144-40}}{2}

\begin{array}{l}{x=\frac{12 \pm \sqrt{144-40}}{2}} \\\\ {x=\frac{12 \pm \sqrt{104}}{2}} \\\\ {x=\frac{12 \pm 2 \sqrt{26}}{2}} \\\\ {x=6 \pm \sqrt{26}=6 \pm 5.1} \\\\ {x=10.1 \text { or } x=0.9}\end{array}

If we take a = 0.9, then while calculating time taken by callie = a - 2 we will end up in negative value

Let us take a = 10.1

So time taken by jerry alone = a = 10.1 hours

Time taken by callie alone = a - 2 = 10.1 - 2 = 8.1 hours

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xxMikexx [17]

Answer:

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Step-by-step explanation:

I think it is D because exponential graphs usually have a curve to them. And the one you need is exponential decay so D is negative and exponential.

HOPE THIS HELPS! HAVE A GREAT DAY!! :)

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