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Aleks [24]
3 years ago
14

Find the circumference of the circle. Use 3.14 for pi

Mathematics
2 answers:
IgorLugansk [536]3 years ago
6 0

Answer:

The circumfrence is 14

Step-by-step explanation:

blondinia [14]3 years ago
5 0
The answer is 21.98



Explanation

3.14 x 7
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What is the answer to this?
irina1246 [14]
R^2=(96/2)^2+14^2

r^2=2500

r=√2500

r=50
3 0
3 years ago
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NemiM [27]

Answer:

what is the question asked?

Step-by-step explanation:

5 0
2 years ago
On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
Find the circumference and the area of the circle with a diameter of 15ft​
guapka [62]

Answer:

Circumference is pi times diameter so that would equal 15 pi. The formula to find the area of a circle is A=pi * r^2 So you divide 15 by 2 to find the radius. r=7.5 Then you square it and multiply it by pi and get 56.25pi which is about equal to 176.715

6 0
3 years ago
The quotient of two and five times a number
trasher [3.6K]
Answer: 2 / 5x
Explanation:
8 0
3 years ago
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