The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:
X² - 5x + 4 = 0
Factor the equation:
(x - 1)(x - 4) = 0
Now calculate each piece separately, starting with the first one:
x - 1 = 0
Add 1 to both sides of the equation:
x = 1
We have proven that x = 1. Now calculate the second piece:
x - 4 = 0
Add 4 to both sides of the equation:
x = 4
We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.
I hope this helps!
-3y-8x+3x^2 is the simplified version of 7y+2x-10y+3x^2-10x
Answer:
A)There is no power of 4 that equals to 0
C) it’s inverse does not have any x-intercepts
Is this from hegarty maths?
20^2+21^2=29^2 can be used to determine if the triangle is a right triangle
