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3 years ago

14

Write down everything that you know about heat temperature pressure and heat transfer

1 answer:

mixer [17]3 years ago

4 0

Answer:

Heat is always transferred from the object at the higher temperature to the object with the lower temperature. For a gas, the heat transfer is related to a change in temperature. The temperature, pressure, and volume of the gas determine the state of the gas. Heating a gas changes the state of the gas.

Explanation:

This is something I know about heat temperature pressure and heat transfer

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98 POINTS PLEASE HELP What can a transistor do in order to fulfill its function in a circuit? Check all that apply.

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Control which layer is the emitter

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Describe how the ancient people follow some natural event to measure time

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Answer: they used seasonal wind, temperature changes, they also used the flooding of rivers. all these are used to tell time

Explanation: the seasons change the climate of the area

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When a surface is illuminated with electromagnetic radiation of wavelength 480 nm, the maximum kinetic energy of the emitted ele

algol [13]

Answer:

Max kinetic energy for 340 nm wavelength will be $2.238\times 10^{-19}j$

Explanation:

In first case wavelength of electromagnetic radiation $\lambda =480nm=480\times 10^{-9}m$

Plank's constant $h=6.6\times 10^{-34}J-s$

Maximum kinetic energy = 0.54 eV

Energy is given by $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{480\times 10^{-9}}=4.125\times 10^{-19}J$

We know that energy is given

$E=K_{MAX}+\Phi$ , here $\Phi$ is work function

So $4.125\times 10^{-19}=0.54\times 10^{-19}+\Phi$

$\Phi =3.585\times 10^{-19}J$

Now wavelength of second radiation = 340 nm

So energy $E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{340\times 10^{-9}}=5.823\times 10^{-19}J$

So $K_{MAX}=5.823\times 10^{-19}-3.585\times 10^{-19}=2.238\times 10^{-19}j$

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4 years ago

WHAT IS THE MASS OF AN OBJECT THAT WEIGHS 100 N?

Finger [1]

Answer:

10.2 kg

Explanation:

Assuming the object is on Earth:

w = mg

m = w / g = 100 / 9.81 = 10.2kg

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3 years ago

If my mass is 196 lbm and I tackle one of my teammates - while decelerating from a velocity of 6.7 m/s to 0 m/s in 0.5 s, how mu

Olin [163]

Answer:

the force acting on the team mate is 1.19 kN.

Explanation:

given,

mass = 196 lbm

while tackling, the deceleration is from velocity 6.7 m/s to 0 m/s

time taken for deceleration = 0.5 sec

F = mass × acceleration

acceleration = $\dfrac{0-6.7}{0.5}$

= -13.4 m/s²

1 lbs = 0.453 kg

196 lbs = 196 × 0.453 = 88.79 kg

F = 88.79 × 13.4

F = 1189.786 N = 1.19 kN

hence, the force acting on the team mate is 1.19 kN.

8 0

3 years ago