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Minchanka [31]
3 years ago
12

Fossils are rare because certain conditions are needed to preserve an organism in order for it to fossilize, and those condition

s themselves are rare. Which of these conditions is LEAST likely to result in fossilization? A) Organism has an exoskeleton. B) Organism lives in or near water. C) Organism lives in a colder climate. D) Organism is prey to several species.
Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

D

Explanation:

The least of the conditions that can result in fossilization would be <u>when an organism is a prey to several species.</u>

Fossils are remains or traces of organisms that have been geological preserved and a prey is an organism that is often hunted and serves as food to bigger organisms. <em>When an organism is eaten, the probability of it becoming a fossil becomes low. Unless such an organism is usually partially eaten by predators, there would not be any remains, let alone being fossilized.</em>

The correct option is D.

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sleet_krkn [62]

We are asked to determine the velocity of a rain drop if it falls from 4 km.

To do that we will use the following formula:

2ah=v_f^2-v_0^2

Where:

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If we assume the initial velocity to be 0 we get:

2ah=v_f^2

The acceleration is the acceleration due to gravity:

2gh=v_f^2

Now, we take the square root to both sides:

\sqrt{2gh}=v_f

Now, we substitute the values:

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solving the operations:

280\frac{m}{s}=v

Therefore, the velocity without air drag is 280 m/s.

Part B. we are asked to determine the velocity if there is air drag. To do that we will use the following formula:

F_d=\frac{1}{2}C\rho_{air}Av^2

Where:

\begin{gathered} F_d=drag\text{ force} \\ C=\text{ constant} \\ \rho_{air}=\text{ density of air} \\ A=\text{ area} \\ v=\text{ velocity} \end{gathered}

We need to determine the drag force. To do that we will use the following free-body diagram:

Since the velocity that the raindrop reaches is the terminal velocity and its a constant velocity this means that the acceleration is zero and therefore the forces are balanced:

F_d=mg

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Where:

\begin{gathered} \rho_{water}=\text{ density of water} \\ V=\text{ volume} \end{gathered}

The volume is the volume of a sphere, therefore:

m=\rho_{water}(\frac{4}{3}\pi r^3)

Since the diameter of the raindrop is 3 millimeters, the radius is 1.5 mm or 0.0015 meters. Substituting we get:

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Solving the operations:

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F_d=(1.39\times10^{-5}kg)(9.8\frac{m}{s^2})

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Now, we solve for the velocity:

\frac{1.36\times10^{-4}N}{\frac{1}{2}C\rho_{air}A}=v^2

Now, we substitute the values. We will use the area of a circle:

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Substituting the radius:

\frac{1.36\cdot10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^{3}})(\pi(0.0015m)^2)}=v^2

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\begin{gathered} \sqrt{70.67\frac{m^2}{s^2}}=v \\  \\ 8.4\frac{m}{s}=v \\  \end{gathered}

Therefore, the velocity is 8.4 m/s

7 0
1 year ago
Answer meeeeeeeeeeeeeee
konstantin123 [22]

Answer:

option A is correct because air friction is greater than gravity

Explanation:

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