Answer:
15km/hr
Explanation:
The average speed for the entire trip is the sum of the total distance traveled divided by the total time of the trip.
Total time = 4hr
distance for the first 3hrs = 50km
distance for the last 1hr = 10km
Total distance = 50km + 10km = 60km
Now;
Average speed =
Insert the parameters and solve;
Average speed = = 15km/hr
From Kepler's 3rd law, time period of satellite orbiting around planet in a circular orbit is given by,
T² = 4π²r³/GM
M= mass of the Earth = 6×10²⁴ Kg.
∴ T² = 4×3.14²×(2.56×10⁷)³/6.67×10⁻¹¹×6×10²⁴
T² = 1653339719
∴ T = 40661.28 seconds.
Answer:
66.7 mph
Explanation:
Average speed = total distance / total time
We know the total distance is 200 miles. We need to find the total time.
During the first trip:
t = 100 mi / 100 mph
t = 1 h
During the second trip:
t = 100 mi / 50 mph
t = 2 h
So the average speed is:
s = 200 mi / 3 h
s = 66.7 mph
Round as needed.
For figure one the “+” are protons and the “-“ are electrons for the second one the middle is the nucleus and the other is the orbit