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bixtya [17]
3 years ago
7

What kind of front means air masses and their boundaries stop moving?

Physics
1 answer:
charle [14.2K]3 years ago
8 0
Answer:  "a stationary front" .
___________________________________
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An upright object 2.80 cm tall is placed 16.0 cm away from the vertex of a concave mirror with a center of curvature of 24.0 cm.
horrorfan [7]

Answer:

f = 12 cm

Explanation:

<u>Center of Curvature</u>:

The center of that hollow sphere, whose part is the spherical mirror, is known as the ‘Center of Curvature’ of  mirror.

<u>The Radius of Curvature</u>:

The radius of that hollow sphere, whose part is the spherical mirror, is known as the ‘Radius of Curvature’ of  mirror. It is the distance from pole to the center of curvature.

<u>Focal Length</u>:

The distance between principal focus and pole is called ‘Focal Length’. It is denoted by ‘F’.

The focal length of the spherical (concave) mirror is approximately equal to half of the radius of curvature:

f = \frac{R}{2}

where,

f = focal length = ?

R = Radius of curvature = 24 cm

Therefore,

f = \frac{24\ cm}{2}

<u>f = 12 cm</u>

8 0
3 years ago
Describe two ways unbalanced forces help you in your day to<br> day life.
Alexxandr [17]

Answer:

  1. we need unbalance force to lift objects
  2. we need unbalance force to drag objects
6 0
3 years ago
Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, c
a_sh-v [17]

Answer:

possibly because the car is running out of gas

Explanation:

6 0
4 years ago
The gravitational force between two objects is 2400 N. What will be the gravitational force between the objects if the mass of o
motikmotik

Answer:

4800N

Explanation:

Lets assume,

Mass of first object = m₁

Mass of second object = m₂

Distance between the two objects = r

Thus the force between the two objects will be

F = \frac{G\times m_{1}\times m_{2}}{r^{2}}

where, G = Universal gravitational constant

Given, F = 2400N

New mass of second object = 2m₂

Now, the force will be

F_{2} = \frac{G\times m_{1}\times 2m_{2}}{r^{2}}

F_{2}= 2\frac{G\times m_{1}\times m_{2}}{r^{2}}

F_{2}= 2F

F_{2}= 2\times2400

Thus, F₂ = 4800N

6 0
3 years ago
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kogti [31]
Starting making jokes and rapping
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3 years ago
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