We have been given that you drop a ball from a window 50 metres above the ground. The ball bounces to 50% of its previous height with each bounce. We are asked to find the total distance traveled by up and down from the time it was dropped from the window until the 25th bounce.
We will use sum of geometric sequence formula to solve our given problem.
, where,
a = First term of sequence,
r = Common ratio,
n = Number of terms.
For our given problem
,
and
.





Therefore, the ball will travel 100 meters and option B is the correct choice.
It is 2.1 inches longer. Plz plz plz give me brainiest answer I only need 3 more to rank up. If u do I will show my work and show the answer as a fraction.
Answer:
center: (-10,-4)
radius: 9
Step-by-step explanation:
Let's start off by moving the 35 to the other side and grouping the x and y terms we have
(x²+20x)+(y²+8y)= -35
Next we take the term with the x coeficcent, divide it by 2, and square it
so
for the x we would do (20/2)²=100
and make sure we add that to the 35
(x²+20x+100)+(y²+8y+16)= -35+100+16
next factor everythign to get
(x+10)²+(y+4)²=81
therefore the center is (-10,-4)
and the radius is √81 or 9
Answer:
- Cos 45=6/x
x=6/cos 45=6√2
x=6√2
tan 45=y/6
y=tan45 ×6
y=6
2.
sin 60=y/10
y=sin60×10
y=5√3
again
Cos 60=x/10
x=½×10
x=5
3.
Sin 45=x/5
x=1/√2×5 or
x=5√2/2
again
y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]
4.
Sin 30=8/x
½×x=8
x=8*2
x=16
again
cos 30= y/x
√3/2×16=y
y=8√3
5.
sin 60=7/x
x=7/[√3/2]
x=14/√3 or 14√3/3
again
cos 60=y/x
½×14√3/3=y
7√3/2=y
y=7√3/2
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