Answer:
implifying
f(x) = lx + 4l + -3
Multiply f * x
fx = lx + 4l + -3
Reorder the terms:
fx = -3 + 4l + lx
Solving
fx = -3 + 4l + lx
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Divide each side by 'x'.
f = -3x-1 + 4lx-1 + l
Simplifying
f = -3x-1 + 4lx-1 + l
Reorder the terms:
f = l + 4lx-1 + -3x-1
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
2x+8y=12 3x-8y=11
If we have to solve by substitution, Take the first equation and divide by 2
2x/2 + 8y/2 =12/2
x+4y = 6
Then subtract 4y from each side
x = 6 -4y
Then substitute this into the second equation
This is best solved by elimination
2x+8y=12
3x-8y=11
----------------
5x = 36
x = 36/5
Step-by-step explanation:
- (√3+√7)(√3+√7)
- (√3)^2+[(√3*√7)+(√3*√7)]+(√7)^2
- 3+2√21+7
- 10+2√21
Answer:
cosine30
Step-by-step explanation:
Answer:
x = - 4 ± 2
Step-by-step explanation:
Given
f(x) = x² + 8x + 4
To find the zeros let f(x) = 0, that is
x² + 8x + 4 = 0 ( subtract 4 from both sides )
x² + 8x = - 4
To solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(4)x + 16 = - 4 + 16
(x + 4)² = 12 ( take the square root of both sides )
x + 4 = ± 
= ± 2 ( subtract 4 from both sides )
x = - 4 ± 2
Thus the zeros are
x = - 4 - 2 and x = - 4 + 2
