Answer:
sue had the busiest day of all
<h2><u>
Answer With Explanation:</u></h2>
<u>Firstly, let's start with <XOZ: =55°</u>
We know that <ZOQ is 70° and angles on a line add up to 180° so we do 180-70=110 110 divided by 2 = 55 so the 2 angles (XOZ & XOP are 55)
<u>Secondly, <OMN, <MON & <ONM = All are 60°</u>
These 2 angles are joined to create an equilateral triangle which always adds up to 180°
So, there are 3 points to this triangle, therefore we divide 180 by 3 which is 60. The angles are 60°
<u>Thirdly, <QON: =55°</u>
This angle lies on the line XON which needs to add up to 180°
As we worked out before, <XOZ was 55°
So, <ZOQ was already given as 70°
We then do 55+70=125 then 180-125=55°
<QON is 55°
(I'm only in Grade 9 LOL)
Answer:
-6x+14<-28
x = x > 7
3x+28<=25
x = x less than or equal to -1
Step-by-step explanation:
Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
Okay try to round the whole number and see if you can solve that should help you
