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Wewaii [24]
3 years ago
12

8 + 3 • 5 - 20 ÷ 4 = ? Please use the order of operations

Mathematics
2 answers:
nalin [4]3 years ago
8 0

We must multiply and divide before adding and subtracting here. Working from left to right, we get:

8 + 15 - 5 = ?

8 + 10 = ?

18 (answer)

expeople1 [14]3 years ago
5 0

You have to use PEMDAS

Parentheses \\ Exponents \\ Multiplication \\ Division \\ Addition \\ Subtraction

You have to do the division and multiplication first.

3 \times 5 = 15 \\ 20 \div 4 = 5

The new equation is:

8+15-5

First do the addition in the beginning:

15 + 8 = 23

At last, subtract 5

23 - 5 = 18

Your answer is 18

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Hans wanted to find the length of the hypotenuse of the triangle. Which statement correctly identifies his error? ​
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Choice 1. He did not square 40, he just multiplied by 2.

Step-by-step explanation:

Step 1:

According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

The hypotenuse measures c cm while the other sides are 40 cm and 9 cm each.

Step 2:

According to the Pythagorean theorem,

9^{2} +40^{2} = c^{2}.

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\sqrt{1681} = c.

This is the correct solution to the given problem. Hans did not square 40, he just multiplied by 2. Which is the first option.

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3 years ago
Estimate the sum of 703 + 620
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When you estimate, you round each number, the add.
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3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

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From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

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3 years ago
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Step-by-step explanation:

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