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2 years ago

Let f(x)=4x^2-3 and g(x)=-x^2+2.Find f+g and state the domain. Then evaluate the sum when x=2

Mathematics

1 answer:

Whitepunk [10]2 years ago

3 0

Answer:

f+g = 3x^2-1. domain = all real numbers. then plug in two wherever there is an x.

f(x)=4*2^2-3, which equals 13

g(x)= -2^2+2, which equals -2

add

f+g when x=2 is 11

Step-by-step explanation:

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nexus9112 [7]

Answer:

7. Mean = 48

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Step-by-step explanation:

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Hope this helps.

3 0

3 years ago

Read 2 more answers

If f(x)=square root 4x+9+2, which inequality can be used to find the domain of f(x)?

jenyasd209 [6]

we have

$f(x)=\sqrt{4x+9} +2$

we know that

The radicand must be greater than or equal to zero

$4x+9 \geq0 \\ 4x\geq -9 \\x\geq -\frac{9}{4} \\ x\geq -2.25$

the domain is is the interval--------> [-2.25,∞)

therefore

<u>the answer is</u>

$4x+9 \geq0$

8 0

3 years ago

Read 2 more answers

if y is the midpoint of xz, y is located at (3,-1), and z is located at (11,-5), find the coordinates of x

svlad2 [7]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ X(\stackrel{x_1}{x}~,~\stackrel{y_1}{y})\qquad Z(\stackrel{x_2}{11}~,~\stackrel{y_2}{-5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{11+x}{2}~~,~~\cfrac{-5+y}{2} \right)=\stackrel{\stackrel{midpoint}{y}}{(3,-1)}\implies \begin{cases} \cfrac{11+x}{2}=3\\[1em] 11+x=6\\ \boxed{x=-5}\\ \cline{1-1} \cfrac{-5+y}{2}=-1\\[1em] -5+y=-2\\ \boxed{y=3} \end{cases}$