Given the graph of the function f(x) = (x - 4)(x + 1).
From the graph, it can be seen that the graph of the function describe a parabola facing up with the vertex at point (1.5, -6.25).
The x-intercepts of the graph are at points (-1, 0) and (4, 0) while the y-intercept is at point (0, -4)
The vertex of a parabola is the point in the parabola where the graph of the function stops decreasing and starts increasing, or vice-versa.
Thus, the function stops decreasing at point (1.5, -6.25) and then starts increasing, this means that for values of x < 1.5 the function is decreasing and since 0 < 1.5, hence, the function is decreasing for the values of x < 0. Hence, the statement that "the function is increasing for all real values of x where x < 0" is not true.
Similally, Given that the function stops decreasing at point (1.5, -6.5), this means that for values of x < 1.5 the function is decreasing and since -1 < 1.5, hence, the function is decreasing for the values of x < -1.
Thus, the statement that the function is increasing for all real values of x where x < –1 and where x > 4 is not true.
<span>With the explanations given above, it can also be seen that the statement that "the function is decreasing for all real values of x where –1 < x < 4" is also not true.</span>
Angle A= angle B
angle C= angle a(2)
a+a+2a=180 (since all triangles equal 180 degrees)
180=4a
180/4
a=45
angle A and angle B both equal 45 degrees. Angle C equals 90 degrees.
Answer:
x = 0
Step-by-step explanation:
d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
Answer:
-4z+4
Step-by-step explanation:
next time uses cymath
