Use the poin-slope form of the equation of a line:-
y - y1 = m(x - x1) (where m = slope and the point is (x1, y1))
Plugging in the given values:-
y - 6 = 2/5(x - 10)
multiplying through by 5:-
5y - 30 = 2(x - 10)
5y - 30 = 2x - 20
5y = 2x + 10
In standard form the equation is
2x - 5y = -10 (answer)
Answer:
if not mistaken is use a compass and draw an arc across both the legs of the given angle
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Range is just input the domain
so find f(-2), f(0) and f(2)
f(-2)=-(-2)²+1=-4+1=-3
f(0)=-(0)²+1=0+1=1
f(2)=-(2)²+1=-4+1=-3
range={-3,1}
Answer:
Step-by-step explanation:
Plug into distance formula:
Points: (5, -2), (3, -4)
sqrt( ((x2 - x1)^2) + ((y2 - y1)^2))
sqrt( ((3 - 5)^2) + ((-4 + 2)^2))
sqrt( 4 + 4)
sqrt8 ≈ 2.8 OR
sqrt8 = 2√2
Answer:
Step-by-stFind the slope of the line that passes through the points shown in the table.
The slope of the line that passes through the points in the table is
.ep explanation:
