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2 years ago

Can some one please help me with this question with the steps please, thanks in advance

Chemistry

1 answer:

tekilochka [14]2 years ago

4 0

The molecular formula for Hydrocarbon = C₄H₁₀

<h3>Further explanation:</h3>

Given

50 ml hydrocarbon

200 ml CO₂

250 ml H₂O

Required

The molecular formula of Hydrocarbon

Solution

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles

So moles Hydrocarbon : CO₂ : H₂O = 50 ml : 200 ml : 250 ml = 1 : 4 : 5

mol C in 1 mol CO₂=1, and for 4 moles CO₂ there are 4 moles C

mol H in 1 mol H₂O =2, and for 5 moles H₂O there are 10 moles H

So mol ratio C : H in compound = C₄H₁₀

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1.) Consider the processes or reactions, indicate which side of the reaction will have the greatest entropy AND explain why. (4

ratelena [41]

Answer:

A. Right side since CO2 has has more entropy than solid CO2

B. Right side since gaseous CO2 is present on right side

C. Left side since more no of gaseous molecules om left side

D. Right side since on heating of water at 52C starts boiling hence more entropy for vapour.

Explanation:

Generally entropy is the measurement of randomness and follows the order gas>liquid>solid

6 0

3 years ago

Number of different bond angles for pbr2f3

kupik [55]

This is very confusing.

5 0

2 years ago

Choose the best option for the precursor to the tosylate intermediate Design a synthesis of cis-2-methylcyclopentyl acetate from

kumpel [21]

Answer:

To synthesize cis-2-methylcyclopentyl from methycyclopentanol, you need to replace the acetate hydroxyl group with acetate by inverting the configuration.

Explanation:

To understand the process, you need to understand the nucleophilic mechanism taking place in the process. This is the first stage of the process. Hydroxide is a poor leaving group, to it must be converted to a good leaving group. To effect the change, it is necessary to use p-toluenesuphate.

p-toluenesuphate is favored because this can be prepared by a reaction that alters none of the bonds attached to the stereogenic center.

The reaction of p-toluensulfonate with potassium acetate in acetic acid effects the conversion to give the final product: cis-2-methylcyclopentyl.

8 0

2 years ago

When the equation

galina1969 [7]

Answer:

The least whole number coefficient for HNO₃ is 6

Explanation:

The chemical equation above is the reaction between calcium orthophosphate and nitric acid.

To balance a chemical equation, we have to consider law of conservation of matter which states that matter can neither be created nor destroyed.

What this law implies is that, whatever we have at the reactant side must be equal to whatever is obtainable at the product side.

The above equation is

Ca₃(PO₄)₂ + HNO₃ → Ca(NO₃)₂ + H₃PO₄

To balance the equation, we'll have to check the number of atoms at each side and possibly balance the equation with the number of moles.

The balanced equation is

Ca₃(PO₄)₂ + 6HNO₃ → 3Ca(NO₃)₂ + 2H₃PO₄

From the balanced equation above, we can see that the number of calcium (Ca), Phosphorus (P), Oxygen(O), Nitrogen(N) and hydrogen (H) are balanced at both sides of the equation.

The least number coefficient for HNO₃ is 6

3 0

2 years ago

PLEASE SOMEONE! The density of the acetic acid solution is 1.05 g/mL. Calculate the %(m/m) of the acetic acid solution (convert

tigry1 [53]

Answer:

The Percentage concentration of acetic acid = 1.39 %

Explanation:

Density of acetic acid solution = 1.05 g/mL

Volume of acetic acid solution = 0.1 L = 100 mL

From the formula, Density = mass / volume; mass = density × volume

Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g

Molar concentration of acetic acid solution = 0.243 mol/L

Molar mass of acetic acid, CH₃COOH = (12 × 2 + 1 ×4 + 16 ×2) = 60 g/mol

From the formula, mass concentration = molar concentration × molar mass

Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L

In one liter of acetic acid solution, there are 14.58 g of acetic acid. Therefore, in 0.1 L, there will be 14.58 × 0.1 = 1.458 g of acetic acid.

Percentage concentration of acetic acid = mass of acetic acid / mass of acetic acid solution × 100%

Percentage concentration of acetic acid = (1.458 / 105) × 100% = 1.39 %

The Percentage concentration of acetic acid = 1.39 %

8 0

2 years ago

Can some one please help me with this question with the steps please, thanks in advance ​

Can some one please help me with this question with the steps please, thanks in advance