Question

(( PLEASE HELP QUICK ))Which expression can be used to calculate the ratio of the rate of effusion of gas A to the rate of effusion of gas B? I cannot remember the effusion formulas
The square root of the molar mass of B ÷ the square root of the molar mass of A

The square root of the molar mass of A ÷ the square root of the molar mass of B

The molar mass of A ÷ the molar mass of B

The molar mass of B ÷ the molar mass of A

Answer 1

Answer:

The square root of the molar mass of B ÷ the square root of the molar mass of A  

Explanation:

Graham’s Law applies to the effusion of gases:

The rate of effusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

$r \propto \dfrac{1}{\sqrt{M}}$

If you have two gases A and B, the ratio of their rates of effusion is

$\dfrac{r_{\text{A}}}{r_{\text{B}}} = \sqrt{\dfrac{M_{\text{B}}}{M_{\text{A}}}}$