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Mashcka [7]
3 years ago
15

me ayudan porfa soy nueva. porque la información se considera útil y necesaria para tomar decisiones autónomas con responsabilid

ad .?.Cómo reconocer que la información es confiable para tomar decisiones ?​
Chemistry
1 answer:
s2008m [1.1K]3 years ago
6 0

Answer:

No estoy seguro de lo que está buscando, pero la información es muy importante para tomar decisiones. sin una cantidad clave de información, ¿cómo podría tomar la decisión de decir ... comprar un automóvil? En general, incluso la menor cantidad de información puede ayudar en el proceso de toma de decisiones. Espero que esto te ayude.

Explanation:

English version:

help me please I'm new. because the information is considered useful and necessary to make autonomous decisions with responsibility. How to recognize that the information is reliable to make decisions?

I'm not sure what you are looking for, but information is very important for making decisions. Without a key amount of information, how could you make the decision to say ... buy a car? In general, even the smallest amount of information can help in the decision-making process. I hope this helps.

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Explanation:  

Hello there!  

1) In this case, for these calorimetry problems, we can realize that since the temperature decreases the reaction is endothermic because it is absorbing heat from the solution, that is why the temperature goes from 22.00 °C to 16.0°C.  

2) Now, for the total heat released by the reaction, we first need to assume that all of it is released by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

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3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case NH4Cl, we proceed as follows:

\Delta _rH=\frac{ Q_{rxn}}{n}\\\\\Delta _rH= \frac{ 4435.04J}{15.0g*\frac{1mol}{53.49g} } *\frac{1kJ}{1000J} \\\\\Delta _rH=15.8kJ/mol

Best regards!  

Best regards!

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