To determine the molar mass of the unknown gas, we use Graham's Law of Effusion where it relates the effusion rates of two gases with their molar masses. It is expressed as r1/r2 = √M2/M1. We calculate as follows:
Let 1 = argon gas 2 = unknown gas
r2 = 0.91r1r1/r2 = 1/0.91
1/0.91 = √M2/M1 = √M2/40M2 = 48.30 g/mol
I heard Magnesium and Oxygen were going out.
So I was like, "OMg!"
The chemical formula for the product is RbBr.
Answer:
C
Explanation:
an index fossil is a fossil from a very short-lived, geographically widespread species known to exist during a specific interval of geological time.
Answer:
The mole fraction composition of the liquid is :
Mole fraction of butane, pentane and hexane are 0.3638,0.3908 and 0.2454 respectively.
Explanation:
Mass of the liquid mixture = 200 g
Percentage of butane = 30%
Mass of butane = 
Moles of butane = 
Percentage of pentane= 40%
Mass of pentane= 
Moles of pentane= 
Percentage of hexane = 100% - 30% - 40% = 30%
Mass of hexane =
Moles of hexane = 
Mole fraction of butane, pentane and hexane : 
