The atmospheric pressure will be:
The pressure of the atmosphere resulting from the mercury column is 0.959 atm
What is atmospheric pressure?
The force that an object experiences from the weight of the air above it per unit area are known as atmospheric pressure.
Given: Height of mercury column = 729 mm Hg
To find: The pressure of the atmosphere
Calculation:
The atmospheric column resulting from the mercury column is calculated as follows:
1 atm =760 mm Hg
So, we can convert the 729 mm Hg to atm, and we get
Atmospheric pressure = 729 x 1 atm / 760 = 0.959 atm
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Answer:
See explanation
Explanation:
On the pH scale acidity ranges from pH values of 0-6.9. Natural rain water is slightly acidic due to the presence of carbon dioxide in the atmosphere which is an anhydride of carbonic acid.
CO2(g) + H2O(l) -------> H2CO3(aq)
B. The equations that turn sulfur to sulfuric acid are;
S(l) + O2(g) -----> SO2(g)
2SO2(l) + O2(g) -----> 2SO3(g)
SO3(g) + H2SO4(l) -----> H2S2O7(l)
H2S2O7(l) + H2O(l) ----> 2H2SO4(l)
-
At pH 6, H^+ concentration = 1 * 10^-6 M
At pH 2, H^+ concentration = 1 * 10^-2 M
Hence;
1 * 10^-2/1 * 10^-6
= 10^4 times more acidic
Answer:
Acid-base
Explanation:
KOH is a strong base, and NH₄Cl is an acid. They react to form a salt and water.
KOH + NH₄Cl ⟶ NH₃ + KCl + H₂O
base acid salt water
Answer:
760 uM
Explanation:
<em>A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97 uM. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 6.0 mL. Calculate the new molarity of magnesium ion in the cell growth medium Be sure your answer has the correct number of significant digits.</em>
The problem here is that the amount of magnesium ion remains the same irrespective of the volume.
Amount of magnesium in the growth medium = <em>molarity x volume</em>
= 97 x 
x 47 x 
= 4.559 x
Then, the volume reduced to 6.0 mL, the new molarity becomes;
<em>molarity = mole/volume </em>
= 4.559 x /6 x = 7.598333 x 
M = 759.83333 uM
To the correct number of significant digits = 760 uM
