I believe the answer is A
Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is 
Explanation:
Dissociation of weak acid is represented as:
cM 0 0
So dissociation constant will be:
Give c= 0.188 M and 
= ?
Putting in the values we get:
Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is
Answer:the answer is a c and e
Explanation:
<span>CH4 will effuse the fastest.
The speed of effusion is proportional to the speed of the gas molecules with faster molecules effusing fast than slower molecules. And the speed of the molecules at any given temperature is inversely related to the mass of the molecules with lighter molecules being faster. So let's take a look at the mass of the candidate molecules and see which is lighter and therefore faster.
CH4 - Molar mass is about 16.
CO - Molar mass is about 28
Ar - Molar mass is about 40
CO2 - Molar mass is about 44
If the 4 options, CH4 (methane) is by far the lightest, and therefore the fastest, so will effuse faster than the other 3 gasses.</span>
Answer:
option B = 0.410 g
Explanation:
The given measurement have five significant figures 41006. this measurement can be rounded to three significant figures i.e, 0.410 g.
All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.
Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.
Zero between the non zero digits are consider significant like 104 consist of three significant figures.
The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.
