Answer:
option C
Explanation:
given,
energy dissipated by the system to the surrounding = 12 J
Work done on the system = 28 J
change in internal energy of the system
Δ U = Q - W
system losses energy = - 12 J
work done = -28 J
Δ U = Q - W
Δ U = -12 -(-28)
Δ U = 16 J
hence, the correct answer is option C
Answer:
M = 0.730*m
V = 0.663*v
Explanation:
Data Given:

Conservation of Momentum:

Energy Balance:

Substitute Eq 2 into Eq 1

Using Eq 1

Cookware manufactures who make pans out of steel only
The weight of an object is mass*acceleration. In this case mass*g.
1000*9.8=9800
So the car has a weight of 9800 N.
Answer:
The work done by the force on the particle is 29.85 J.
Explanation:
The work is given by:

Where:
x₁: is the lower limit = 0 m
x₂: is the upper limit = 1.9 m
Fₓ: is the force in the horizontal direction = (4.5 + 13.7x - 1.5x²)N

Therefore, the work done by the force on the particle is 29.85 J.
I hope it helps you!