Explanation:
SUPONIENDO QUE LA ACELERACIÓN DE LA GRAVEDAD ES 
USANDO LA SEGUNDA LEY DE NEWTON:
<em>m</em> = 80.0 N/
= 8.16 kg
Instantaneous velocity is the velocity at a specific instant in time. I bet you are taking Honors Physics.
Adlerian therapy is a method in which a therapist collaborates with a client to pinpoint challenges and develop successful solutions for achieving their objectives.
Key Takeaways: Adlerian Therapy
Individual therapy, often known as Adlerian therapy, places an emphasis on the patient's capacity to effect good change in his or her own life.
Adlerian therapy consists of four stages: engagement, assessment, insight, and reorientation.
In Adler’s theory, individuals work to overcome feelings of inferiority and to act in ways that benefit the social interest.
Four Stages of Adlerian Therapy :
Engagement
Assessment
Insight
Reorientation
To learn more about Adlerian Therapy refer : brainly.com/question/11722417
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Answer:
The mass is 
Explanation:
From the question we are told that
The extension of the rod is 
The area is 
The density increase as follows 
The equation 
at

So

=> 
So at
, 
So

=> 
Now

![m = 8 [{2.5 +\frac{ 1.27x^2}{2} } ]\left | 13} \atop {0}} \right.](https://tex.z-dn.net/?f=m%20%20%3D%20%208%20%20%20%5B%7B2.5%20%2B%5Cfrac%7B%201.27x%5E2%7D%7B2%7D%20%7D%20%5D%5Cleft%20%20%7C%2013%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
![m = 8 [{2.5 +\frac{ 1.27(13)^2}{2} } ]](https://tex.z-dn.net/?f=m%20%20%3D%20%208%20%20%20%5B%7B2.5%20%2B%5Cfrac%7B%201.27%2813%29%5E2%7D%7B2%7D%20%7D%20%5D)

