Ask question

Ask question

All categories

Misha Larkins [42]

3 years ago

6

You push your bike with an average pedaling force of 150N over a distance of 20 m going uphill. How much energy have you transfe

rred to the bike?

1 answer:

kodGreya [7K]3 years ago

3 0

Answer:

jojo reference

Explanation:

You might be interested in

Celina has a water sample that’s contaminated with salt and microorganisms. Which method should she use to purify the water?

emmasim [6.3K]

Boil the water to get remove the salt and then use filter paper to remove the microorganisms

3 0

4 years ago

A 2 kg mass connected to a spring with spring constant k = 10 N/m oscillates in simple harmonic motion with an amplitude of A =

insens350 [35]

Answer:

Kinetic energy at 0.05 m is 0.037 J

Explanation:

Given:

Mass, m = 2 kg

Spring constant, k = 10 N/m

Amplitude, A = 0.1 m

Angular frequency, ω = √k/m

Substitute the suitable values in the above equation.

$\omega = \sqrt\frac{10}{2}$

ω = 2.24 s⁻¹

Simple harmonic equation is represent by the equation:

x = A cos ωt

Substitute 0.05 m for x, 0.1 m for A and 2.24 s⁻¹ for ω in the above equation.

$0.05 = 0.1\cos(2.24t)$

t = 0.47 s

Kinetic energy at x = 0.05 is determine by the relation:

$E=\frac{1}{2} kA^{2}\sin^{2}(\omega t)$

Substitute the suitable values in the above equation.

$E=\frac{1}{2} \times 10 \times 0.1^{2} \sin^{2}(2.24\times0.47)$

E = 0.037 J

5 0

3 years ago

Please help me guys <br>a.<br>b.<br>c.

Mademuasel [1]

Answer:

I think its b lol correct me if I'm wrong

6 0

3 years ago

On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the

EastWind [94]

Answer:

ω = √(2T / (mL))

Explanation:

(a) Draw a free body diagram of the mass. There are two tension forces, one pulling down and left, the other pulling down and right.

The x-components of the tension forces cancel each other out, so the net force is in the y direction:

∑F = -2T sin θ, where θ is the angle from the horizontal.

For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m). (This is derived by solving a second order differential equation.)

In this case, k = 2T/L, so the frequency is:

ω = √((2T/L) / m)

ω = √(2T / (mL))

6 0

3 years ago

If the mass of an object is 100 and Net force is 400, what would be the Acceleration?

ira [324]

Answer:

$4m/s^{2}$

Explanation:

I'm assuming the units for force and mass are Newtons and kilograms, respectively.

Rearranging Newton's first law (F=m*a) to solve for acceleration:

F=m*a

$a=\frac{F}{m}=\frac{400 N}{100 kg}=4m/s^{2}$

The acceleration is 4 meters per second squared and was found by rearranging Newton's first law in order to solve for acceleration.

8 0

3 years ago