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exis [7]
3 years ago
5

Nathan is standing 2 feet away from a plane mirror. Hiva is standing 5 feet further than

Physics
1 answer:
Viktor [21]3 years ago
3 0

Answer:

They are standing 3 feet away from each other

Explanation:

If Nathan Is standing 2 feet away from the mirror. Then Hiva is standing 7 feet away from the mirror is she is standing 5 feet further than him. They are standing 3 feet away from each other.

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3 light-years =________.
KATRIN_1 [288]

               ( 3 yr) · (186,282.397 mile/s) · (86,400 s/day) · (365 day/yr)

           =  (3 · 186,282.397 · 86,400 · 365)  mile

           =      1.762380502 x 10¹³  miles

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3 years ago
A 1.50 3 103 - kg car starts from rest and accelerates uniformly to 18.0 m/s in 12.0 s. Assume that air resistance remains const
nexus9112 [7]

Answer:

Explanation:

let force exerted by engine be F.Net force =( F-400)N, applying newton law

     F-400 = 1.5 x 10³x18 =27000 ,

F = 27400 N.

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Average velocity = (0 + 216 )/2 = 108 m/s

Average power = force x average velocity = 27400 x 108 = 29.6 10⁵ W .⁶

b) At 12 s , velocity = 216 m/s

Instantaneous power = velocity x force = 216 x 27400 = 59.2 x 10⁶ W.

8 0
3 years ago
Read 2 more answers
The vector position of an object is given by r what is the torque acting on the object about the origin when a force f = (−12.5i
attashe74 [19]
Let the vector position of the object in the (x-y) plane be 
\vec{r} = x \hat{i} + y \hat{j}

The applied force is
\vec{f} = -12.5 \hat{i}


By definition, the applied torque is
\vec{T} = \vec{r} \times \vec{f} = (x\hat{i} + y\hat{j}) \times (-12.5y \hat{i}) = 12.5\hat{k}

Answer: 12.5y \, \hat{k}

7 0
3 years ago
PLEASE HELP ME SOMEONE
sasho [114]
I think its B or D, most likely D.
7 0
3 years ago
The 2.6-kg collar is released from rest at A and slides down the inclined fixed rod in the vertical plane. The coefficient of ki
neonofarm [45]

Answer:

The attached diagram explains the system,

Sum of Fy = 0

N=9.81

N - mgCos60 = 0

F= ukN= (0.53)(9.81) =

F= 5.12 N

So

F.d= 1/2(mv.v) - mgdsin60

-5.12*0.5 = 0.5*v^2 - 2*(9.81)*(0.5*sin60)

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For deflection

-F.x = 1/2(mv.v) - mgxsin60 + 1/2 (k*x*x)

by solving for with values of v, m, g, F, k

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(b) x = 0.093 m

correct Answer is 0.093m

Explanation:

3 0
3 years ago
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