If he moves the piano 4 meters, with 700 newtons of force
in the direction of the motion, then the work done is
Work = (force) x (distance)
= (700 N) x (4 m) = 2,800 joules .
If he does all of that in 2 seconds, then
he did it at the rate of
(work) / (time) = (2,800 J) / (2 sec) = 1,400 watts
(about 1.88 'horsepower' !)
Let say the circle is of radius R
then one lap is means the total distance the total length of the circle
here the length of circle is same as circumference
so it is given as
So here the length of lap is given as length of circle which is given as above
The time taken for him to move the bin 6.5 m is 2.30 s.
The given parameters;
- <em>weight of the load, w = 557 N</em>
- <em>force applied , F = 410 N</em>
- <em>angle of force, = 15°</em>
- <em>coefficient of kinetic friction = 0.46</em>
- <em>distance moved, d = 6.5 m</em>
The net horizontal force on the recycling bin is calculated as follows;
where;
- <em>m is the mass of the recycling bin</em>
- <em /><em> is the frictional force </em>
W = mg
The net horizontal force on the recycling bin is calculated as;
The time taken for him to move the bin 6.5 m is calculated as follows;
Thus, the time taken for him to move the bin 6.5 m is 2.30 s.
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