Answer:
w = 0.173 N
Explanation:
The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.
The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:
y(t) = v_0 * t + y_0 - 0.5 * g * t^2
y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.
v_0 is the initial velocity, in this case v_0 = 0 m/s.
y_0 is the initial position of the ball, in this case it is 10 m.
g is the gravity that we want to know.
Applying these values in the equation we have:
0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2
0 = 10 - 0.5*11.56*g
0 = 10 -5.78*g
5.78*g = 10
g = 1.73 m/s^2
Then we can use this value to find out the weigh of the ball in that planet:
w = g*m = 0.1*1.73 = 0.173 N
Answer:
A. 6.282
B. 2.03kg
Explanation:
A.
We solve using archimedes principle
L³pwood = L²dwater
We make d subject of the formula
d = Lpwood/pester
= 18x651/1000
= 18x0.651
= 11.718cm
Distance from horizontal top to water level
= 18-11.718
= 6.282cm
B.
When we place lead block
WL + L³pwoodg = L³pwaterg
WL = L³g(Pwater-Pwood)
= 0.18³x9.8(1000-651)
= 19.94N
19.94/9.8
= 2.03kg
The mass m is therefore 2.03kg
<h3><u>Answer and explanation;</u></h3>
- <u><em>A neutral sodium atom contains 11 protons, 12 neutrons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1.</em></u> Thus; Sodium atom is neutral whereas sodium ion is a charged species with a charge of +1.
- <u><em>Sodium ion is positively charged. In sodium ion, there are 11 protons and 12 neutrons but 10 electrons</em></u>, i.e., sodium ion contains lesser number of electrons. Additionally,the size of sodium ion is smaller than that of sodium atom.
The 102N acting on the ropes being pulled by eric and kim have some of that force acting horizontally, and some of it vertically. By visualizing it as a right angled triangle, with the hypotenuse the length of the diagonal force, and each side the length of the horizontal and vertical forces, you can use trigonometry to calculate the length of the vertical force. You are told that it is at an angle of 30 with the vertical rope, therefore you know the length of the hypotenuse, and the angle between it and the vertical force, so using trig: (vertical force=x)
x/102=cos(30)
x=102*cos(30)
x=88.33
Therefore the diagonal ropes give a vertical force of 88.33N, and the centre rope, as it acts vertically, gives a vertical force of all 102N. The total:
88.33*2+102=278.66N
I don't know if this is very clear, I hope its good enough to help. If you don't understand, just ask, and I can answer any questions!!! :)