The coach has not seen improvement as expected in his team and plans to change practice session. To help the players he changes
1 answer:
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Answer:
A
Explanation:
The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:
More precisely, the strength of the field at a distance r from the centre of the sphere is
where k is the Coulomb's constant and Q is the charge on the sphere.
From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.
This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.
Answer:
a) 24
b) 3.3 sec
c) 29.8 m/s
d) 48.85 m
Explanation:
a)
α = angular acceleration = - 28.4 rad/s²
r = radius of the tire = 0.32 m
w₀ = initial angular velocity = 93 rad/s
w = final angular velocity = 0 rad/s
θ = angular displacement
Using the equation
w² = w₀² + 2αθ
0² = 93² + 2 (- 28.4) θ
θ = 152.3 rad
n = number of revolutions
Number of revolutions are given as
b)
t = time taken to stop
using the equation
w = w₀ + αt
0 = 93 + (- 28.4) t
t = 3.3 sec
c)
v₀ = initial velocity of the car
initial velocity of the car is given as
v₀ = r w₀ = (0.32) (93) = 29.8 m/s
d)
v = final velocity = 0 m/s
a = linear acceleration = rα = (0.32) (- 28.4) = - 9.09 m/s²
d = distance traveled by car before stopping
Using the equation
v² = v₀² + 2 a d
0² = 29.8² + 2 (- 9.09) d
d = 48.85 m