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Drupady [299]
3 years ago
7

HELP HELP HELP*. Hei has $1,700 in a retirement account earning 4% interest compounded annually. Each year after the first, she

makes additional deposits of $1,700. After 5 years, what was her account balance if she did not make any withdrawals? Round each year's interest to the nearest cent if necessary.
what was account balance after 5 years
Mathematics
1 answer:
KatRina [158]3 years ago
8 0

~~~~~~~~~~~~\stackrel{\textit{payments at the beginning of the period}}{\textit{Future Value of an annuity due}}\\ ~~~~~~~~~~~~ \\\\ A=pmt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]\left(1+\frac{r}{n}\right)

\begin{cases} A=\textit{accumulated amount} \\ pmt=\textit{periodic payments}\dotfill &1700\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=1700\left[ \cfrac{\left( 1+\frac{0.04}{1} \right)^{1\cdot 5}-1}{\frac{0.04}{1}} \right]\left(1+\frac{0.04}{1}\right) \\\\\\ A=1700\left( \cfrac{1.04^5~~ - ~~1}{0.04} \right)(1.04)\implies A\approx 9576.06

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andrew-mc [135]

Answer:

<h2>10</h2>

Step-by-step explanation:

Given the function f(x, y) = 2 sin(xy) at (0,5), the maximum rate of change of the function at that point will occur in the direction \nabla f(0,5)

\nabla f(x, y) = \frac{\delta(2sin(xy)) }{\delta x} i + \frac{\delta(2sin(xy)) }{\delta y} j\\\\\nabla f(x, y) = 2ycos(xy)i + 2xcos(xy)j\\\\\nabla f(0, 5) =  2(5)cos(0*5)i + 2(0)cos(0*5)j\\\\\nabla f(0, 5) = 10cos0i+ 0j\\\\\nabla f(0, 5) = 10i+0j\\\\||\nabla f(0, 5)|| = \sqrt{10^2+0^2} \\\\||\nabla f(0, 5)||  = \sqrt{100} = 10

Hence, the magnitude of the maximum rate of the function at the point (0, 5) is 10

6 0
3 years ago
Find the distance from p to l. line l contains points (-2,0 and (4,8 and point p coordinates (5,1
svet-max [94.6K]
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7 0
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julia-pushkina [17]

The given expression can be written as q^{2} +12q+32 = (q+8)(q+4).

Step-by-step explanation:

Given,

q^{2} +12q+32

To make it a complete square.

Formula

(a+b)² = a^{2} +2ab+b^{2}

a^{2} -b^{2} = (a+b)(a-b)

Now,

q^{2} +12q+32

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7 0
3 years ago
YO PLEASE HELP N ONLY ANSWER IF U KNOW THE ANSWER!!
Ronch [10]
HOPE THIS HELPS YOU..... :)

7 0
3 years ago
Solve for x:
quester [9]
-3/2 × x - 9 = -27
+ 9
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× 2
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-6x = -36
÷ -6
x = 6
Hope this helps! Let me know if I've confused you or anything
3 0
4 years ago
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