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1 year ago

Keith writes the numbers 1 to 20 on pieces of paper and places them in a hat.

1 answer:

4 0

To get the answer use what you know divide it and use Algebra if you know any and also ask for help scan your math that’s what Brainly is for trust me

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What happens to the value of the expression 80-2r80−2r80, minus, 2, r as rrr decreases? Choose 1 answer: Choose 1 answer: (Choic

Pie

Answer:

(Choice B) B It decreases.

Step-by-step explanation:

According to the situation, the solution of the value of the expression is as follows

Let us assume

r 80 -2r

5 80 - 10 = 70

4 80 - 8 = 72

3 80 - 6 = 74

2 80 - 4 = 76

1 80 - 2 = 78

As we can from the above calculation that expression value risen if r value decreased

Therefore the correct option is B.

6 0

2 years ago

Read 2 more answers

DUE TODAY!

Leokris [45]

<em>Independent variables are variables of a quantity that are not affected by any conditions. </em>

<em>Dependent variables are variables of a quantity that change if conditions relative to that variable changes.</em>

For example, we generally we take x as independent variable by x variable and dependent variable by y variable.

To find the rate of change we get two values of independent variable (x's) and two values of dependent variables (y's) to get two coordinates in form of

(x,1,y1) and (x2,y2).

<h3>And we can find the rate of change by applying slope formula</h3>

$m= \frac{y_2-y_1}{x_2-x_1}$ .

3 0

2 years ago

Find the value of the expression.

Jlenok [28]

Answer:

according to your question it should be 3.00x 10^18 which is not a choice

5 0

2 years ago

Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions) Please

snow_lady [41]

Answer:

a) See attachment 1.

b) t² and D

c) See attachment 2.

d) g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

See attachment 1. The line of best fit is shown in red.

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

Make a table of values of t² and D:

$\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}$

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0). Therefore, use these two points to find the slope of the line:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2$