Each coin has a head and a tail, therefore when you toss two coins, you have 4 possible outcomes. You have two heads in only one of these outcomes, while the other three have at least one tail.
The expected value of the game is the price paid/gained times the probability of loss/victory:
E = (1 / 4) · (-6) + (3 / 4) · (2)
= -3 / 2 + 3 / 2
= 0
Bob expects to tie with Will.
I think what you mean is:
Then using our rules of exponents, this is the same as
Answer:
10m - 16
It's basically the same thing but simplified to make it easier to solve.
Step-by-step explanation:
3(4m-2)-2(m+5)
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Distribution
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12m-6-2m-10
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Combining Like Terms
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10m-16
