Answer:
B
Step-by-step explanation:
THATSS ALL I NOW IT SOO GOOD
Answer:
Here we have the function:
y = f(x) = 3^x
Using the values:
x and (x + 1)
We need to find that the y-value increases by a factor of 3.
So we need to prove that:
f(x + 1) = 3*f(x).
Or we can see the quotient:
f(x + 1)/f(x) = 3
Here we can find the values:
f(x + 1) = y = 3^(x + 1)
f(x) = y' = 3^x
If we take the quotient, we get:

Here we can use the properties:


Using these in the quotient equation we get:

Then:


So we found that the y-value increases by a factor of 3 between any two points x₂ and x₁ such that: x₂ - x₁ = 1.
Probability of any event = ( favourable outcomes ) /total number of outcomes
Probability of = 3/10 + 2/9 = 
Based on the given values above, here is the solution to find if how many ants there will be after 10 weeks and 20 weeks.
Since the population increases by 12%. we need to get 12% of the population every week.
500 x .12 = 60.
1st week = 560
2nd week = 627.2
3rd week = 702. 46
4th week = 786.76
5th week = 881. 17
6th week = 986.91
7th week= 1,105.34
8th week= 1,237.98
9th week= 1, 386.54
10th week = 1, 552.92
11th week = 1,739.27
12th week = 1,947.98
13th week= 2,181.74
14th week=2, 443.55
15th week = 2,736.76
16th week = 3, 065. 17
17th week = 3,432.99
18th week= 3,844.95
19th week= 4,306.34
20th week = 4,823.10
Therefore, after 10 weeks, there will be 1,553 ants and after 20 weeks, there will be 4,823 ants.