Here
are the answers for the two ions:
<span>1.
For K+, this would be the answer: Zeff
= 19 - (0.35(7) + 0.85(8) +2) = 7.75</span>
2. For CI-, Zeff = 17 - (0.35(7) + 0.85(8) +2) = 5.75
I am hoping that these answers have satisfied your queries and
it will be able to help you.
Answer:
<em><u>Step by step explanation</u></em><em><u>:</u></em>
<em>Given:</em>
Mass of given sample (m) = 2.50 g
Initial temperature (T1) = 25°C
Final temperature (T2) = 20°C
Heat Energy Q = 12 cal
<em>T</em><em>o </em><em>find:</em>
<em></em>
<em>Solution</em><em>:</em>
We know that,
<em>Specific</em><em> </em><em>heat</em> <em>of </em><em>any </em><em>substance </em><em>is </em><em>directly</em><em> </em><em>proportional</em><em> </em><em>to </em><em>the </em><em>mass </em><em>and </em><em>change </em><em>in </em><em>temperature.</em>
Represented by equation,
Where,
<em>Q = Heat Energy</em>
<em>m = mass of given sampl</em><em>e</em>
<em>c = specific heat</em>
<em>∆T = change in </em><em>temperature</em>
Substituting corresponding values,
<em></em>
We also know that,
multiplying above answer by 4.184,
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Given;
no. of moles (n) = 500 moles
volume (V) = 1.2 l
temperature (T) = 150°C = (150 + 273 )k = 423 k
gas constant (R) = 0.0821 L- atm / mole-K
then,
PV = nRT
P × 1.2 = 500 × 0.0821 × 423
P = 14,470.125 atm
But I guess pressure is too high. Well this should be the way.