Question

Assuming the diameters of the nucleus and atom are 10−4 å and 1 - 5 å correspondingly, what fraction of the volume of the atom is taken up by the nucleus?

Answer 1

The diameter of nucleus = 10₁$10^{-4}$ A° and atom = 1.5 A°. Radius of nucleus = $\frac{10^{-4} }{2}$ A° and radius of atom = $\frac{1.5}{2}$ A°. The fraction of volume taken by nucleus = $\frac{volume of nuclues}{Volume of atom}$ = $\frac{4}{3}\pi\(\frac{(10^{-4} }{2})^{3}$/$\frac{4}{3}\pi\(\frac{(10^{-4} }{2})^{3}$.

Or, $\frac{10^{-4} }{1.5})^{3}$= 2.95×$10^{-13}$. This is the fraction of volume of nucleus in atom.