Answer:
a) 2.188
b) John's rent is not an outlier
c) His rent has to be higher than $1,235 to be an outlier
Step-by-step explanation:
The mean monthly rent of students at Oxnard University is $780 with a standard deviation of $208.
(a) John’s rent is $1,235. What is his standardized z-score?
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $1235
μ is the population mean = $780
σ is the population standard deviation = $208
Hence,
z = 1235 - 780/208
z = 2.1875
Approximately to 3 decimal place = 2.188
(b) Is John’s rent an outlier?
No it isn't
(c) How high would the rent have to be to qualify as an outlier?
John’s rent would have to be higher than $1235
Answer:
1
Step-by-step explanation:
Given expression:

Following the <u>order of operations</u>, carry out the operations inside the parentheses first:





Convert 27 to a fraction:

Cross cancel the common factor:



Answer:
-4,-5?
Step-by-step explanation:
Answer:
Yes
Step-by-step explanation:
Your are correct