Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
Its the letter G because 17.64 divided by 7 is 2.52
First answer is 27
Multiply -3 with -1
Then multiply it to the 3rd power.
2nd answer is 1 / 1296
First add the expoinents
-12 +8 = -4
Then you would need to do the equation
6^-4 x 6^0
And this would equal 1/1296
Please mark Brainliest :)
Answer:
126/1=126
Step-by-step explanation:
630:5 as a fraction would be 630/5.
630/5 simplified would be 126/1.
Hope this helps :)
- First we calculate the product of the denominator.
- Then we calculate the quotient of the numerator.
- We multiply the exponents of the expression.
<h3><em><u>MissSpanish</u></em></h3>
